NO

Problem:
 2nd(cons(X)) -> 2nd(cons1(X,X1))
 2nd(cons1(X,cons(Y))) -> Y
 from(X) -> cons(X)

Proof:
 Fresh Variable Processor:
  loop length: 1
  terms:
   2nd(cons(X))
  context: 2nd(cons1(X,[]))
  substitution:
   X1 -> 2nd(cons(X))
  Qed