YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 61 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 9 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 0 ms] (6) QTRS (7) QTRSRRRProof [EQUIVALENT, 0 ms] (8) QTRS (9) RisEmptyProof [EQUIVALENT, 0 ms] (10) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(X) -> if(X, c, n__f(n__true)) if(true, X, Y) -> X if(false, X, Y) -> activate(Y) f(X) -> n__f(X) true -> n__true activate(n__f(X)) -> f(activate(X)) activate(n__true) -> true activate(X) -> X Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(activate(x_1)) = x_1 POL(c) = 0 POL(f(x_1)) = 2*x_1 POL(false) = 1 POL(if(x_1, x_2, x_3)) = x_1 + x_2 + 2*x_3 POL(n__f(x_1)) = 2*x_1 POL(n__true) = 0 POL(true) = 0 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: if(false, X, Y) -> activate(Y) ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(X) -> if(X, c, n__f(n__true)) if(true, X, Y) -> X f(X) -> n__f(X) true -> n__true activate(n__f(X)) -> f(activate(X)) activate(n__true) -> true activate(X) -> X Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(activate(x_1)) = 2 + 2*x_1 POL(c) = 0 POL(f(x_1)) = 2 + 2*x_1 POL(if(x_1, x_2, x_3)) = x_1 + x_2 + x_3 POL(n__f(x_1)) = 2 + 2*x_1 POL(n__true) = 0 POL(true) = 1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: if(true, X, Y) -> X true -> n__true activate(n__true) -> true activate(X) -> X ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(X) -> if(X, c, n__f(n__true)) f(X) -> n__f(X) activate(n__f(X)) -> f(activate(X)) Q is empty. ---------------------------------------- (5) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(activate(x_1)) = 2*x_1 POL(c) = 0 POL(f(x_1)) = 2 + 2*x_1 POL(if(x_1, x_2, x_3)) = 2*x_1 + x_2 + x_3 POL(n__f(x_1)) = 2 + 2*x_1 POL(n__true) = 0 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: activate(n__f(X)) -> f(activate(X)) ---------------------------------------- (6) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(X) -> if(X, c, n__f(n__true)) f(X) -> n__f(X) Q is empty. ---------------------------------------- (7) QTRSRRRProof (EQUIVALENT) Used ordering: Knuth-Bendix order [KBO] with precedence:n__true > n__f_1 > c > f_1 > if_3 and weight map: c=1 n__true=1 f_1=3 n__f_1=1 if_3=0 The variable weight is 1With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: f(X) -> if(X, c, n__f(n__true)) f(X) -> n__f(X) ---------------------------------------- (8) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (9) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (10) YES