YES Problem: active(c()) -> mark(f(g(c()))) active(f(g(X))) -> mark(g(X)) proper(c()) -> ok(c()) proper(f(X)) -> f(proper(X)) proper(g(X)) -> g(proper(X)) f(ok(X)) -> ok(f(X)) g(ok(X)) -> ok(g(X)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 1 1] [mark](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [active](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [f](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [proper](x0) = [0 0 0]x0 [0 1 0] , [0] [c] = [1] [0], [1 0 1] [top](x0) = [0 0 0]x0 [1 0 1] , [1 0 0] [ok](x0) = [0 0 0]x0 [0 1 0] , [1 0 0] [g](x0) = [0 0 0]x0 [0 0 0] orientation: [1] [0] active(c()) = [0] >= [0] = mark(f(g(c()))) [0] [0] [1 0 0] [1 0 0] active(f(g(X))) = [0 0 0]X >= [0 0 0]X = mark(g(X)) [0 0 0] [0 0 0] [0] [0] proper(c()) = [0] >= [0] = ok(c()) [1] [1] [1 0 0] [1 0 0] proper(f(X)) = [0 0 0]X >= [0 0 0]X = f(proper(X)) [0 0 0] [0 0 0] [1 0 0] [1 0 0] proper(g(X)) = [0 0 0]X >= [0 0 0]X = g(proper(X)) [0 0 0] [0 0 0] [1 0 0] [1 0 0] f(ok(X)) = [0 0 0]X >= [0 0 0]X = ok(f(X)) [0 0 0] [0 0 0] [1 0 0] [1 0 0] g(ok(X)) = [0 0 0]X >= [0 0 0]X = ok(g(X)) [0 0 0] [0 0 0] [1 1 1] [1 1 0] top(mark(X)) = [0 0 0]X >= [0 0 0]X = top(proper(X)) [1 1 1] [1 1 0] [1 1 0] [1 1 0] top(ok(X)) = [0 0 0]X >= [0 0 0]X = top(active(X)) [1 1 0] [1 1 0] problem: active(f(g(X))) -> mark(g(X)) proper(c()) -> ok(c()) proper(f(X)) -> f(proper(X)) proper(g(X)) -> g(proper(X)) f(ok(X)) -> ok(f(X)) g(ok(X)) -> ok(g(X)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Matrix Interpretation Processor: dim=1 interpretation: [mark](x0) = 4x0, [active](x0) = x0, [f](x0) = 6x0 + 6, [proper](x0) = 4x0, [c] = 4, [top](x0) = x0, [ok](x0) = 2x0 + 4, [g](x0) = 4x0 + 4 orientation: active(f(g(X))) = 24X + 30 >= 16X + 16 = mark(g(X)) proper(c()) = 16 >= 12 = ok(c()) proper(f(X)) = 24X + 24 >= 24X + 6 = f(proper(X)) proper(g(X)) = 16X + 16 >= 16X + 4 = g(proper(X)) f(ok(X)) = 12X + 30 >= 12X + 16 = ok(f(X)) g(ok(X)) = 8X + 20 >= 8X + 12 = ok(g(X)) top(mark(X)) = 4X >= 4X = top(proper(X)) top(ok(X)) = 2X + 4 >= X = top(active(X)) problem: top(mark(X)) -> top(proper(X)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [0] [mark](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [1 0 0] [proper](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [top](x0) = [0 0 0]x0 [0 0 0] orientation: [1 0 0] [1] [1 0 0] top(mark(X)) = [0 0 0]X + [0] >= [0 0 0]X = top(proper(X)) [0 0 0] [0] [0 0 0] problem: Qed