NO Prover = TRS(tech=GUIDED_UNF, nb_unfoldings=unlimited, unfold_variables=true, strategy=LEFTMOST_NE) ** BEGIN proof argument ** The following rule was generated while unfolding the analyzed TRS: [iteration = 5] f(b,b) -> f(b,b) Let l be the left-hand side and r be the right-hand side of this rule. Let p = epsilon, theta1 = {} and theta2 = {}. We have r|p = f(b,b) and theta2(theta1(l)) = theta1(r|p). Hence, the term theta1(l) = f(b,b) loops w.r.t. the analyzed TRS. ** END proof argument ** ** BEGIN proof description ** ## Searching for a generalized rewrite rule (a rule whose right-hand side contains a variable that does not occur in the left-hand side)... No generalized rewrite rule found! ## Searching for a loop by unfolding (unfolding of variable subterms: ON)... # Iteration 0: no loop detected, 1 unfolded rule generated. # Iteration 1: no loop detected, 1 unfolded rule generated. # Iteration 2: no loop detected, 1 unfolded rule generated. # Iteration 3: no loop detected, 1 unfolded rule generated. # Iteration 4: no loop detected, 4 unfolded rules generated. # Iteration 5: loop detected, 1 unfolded rule generated. Here is the successful unfolding. Let IR be the TRS under analysis. L0 = [f^#(_0,_0) -> h^#(a), h^#(_1) -> g^#(_1,_1), g^#(a,_2) -> f^#(b,activate(_2))] is in U_IR^0. We merge the first and the second rule of L0. ==> L1 = [f^#(_0,_0) -> g^#(a,a), g^#(a,_1) -> f^#(b,activate(_1))] is in U_IR^1. We merge the first and the second rule of L1. ==> L2 = f^#(_0,_0) -> f^#(b,activate(a)) is in U_IR^2. Let p2 = [0]. The subterm at position p2 in the left-hand side of the rule of L2 unifies with the subterm at position p2 in the right-hand side of the rule of L2. ==> L3 = f^#(b,b) -> f^#(b,activate(a)) is in U_IR^3. Let p3 = [1]. We unfold the rule of L3 forwards at position p3 with the rule activate(_0) -> _0. ==> L4 = f^#(b,b) -> f^#(b,a) is in U_IR^4. Let p4 = [1]. We unfold the rule of L4 forwards at position p4 with the rule a -> b. ==> L5 = f^#(b,b) -> f^#(b,b) is in U_IR^5. ** END proof description ** Proof stopped at iteration 5 Number of unfolded rules generated by this proof = 9 Number of unfolded rules generated by all the parallel proofs = 9