YES Problem: c(c(b(c(x)))) -> b(a(0(),c(x))) c(c(x)) -> b(c(b(c(x)))) a(0(),x) -> c(c(x)) Proof: DP Processor: DPs: c#(c(b(c(x)))) -> a#(0(),c(x)) c#(c(x)) -> c#(b(c(x))) a#(0(),x) -> c#(x) a#(0(),x) -> c#(c(x)) TRS: c(c(b(c(x)))) -> b(a(0(),c(x))) c(c(x)) -> b(c(b(c(x)))) a(0(),x) -> c(c(x)) TDG Processor: DPs: c#(c(b(c(x)))) -> a#(0(),c(x)) c#(c(x)) -> c#(b(c(x))) a#(0(),x) -> c#(x) a#(0(),x) -> c#(c(x)) TRS: c(c(b(c(x)))) -> b(a(0(),c(x))) c(c(x)) -> b(c(b(c(x)))) a(0(),x) -> c(c(x)) graph: a#(0(),x) -> c#(c(x)) -> c#(c(x)) -> c#(b(c(x))) a#(0(),x) -> c#(c(x)) -> c#(c(b(c(x)))) -> a#(0(),c(x)) a#(0(),x) -> c#(x) -> c#(c(x)) -> c#(b(c(x))) a#(0(),x) -> c#(x) -> c#(c(b(c(x)))) -> a#(0(),c(x)) c#(c(b(c(x)))) -> a#(0(),c(x)) -> a#(0(),x) -> c#(c(x)) c#(c(b(c(x)))) -> a#(0(),c(x)) -> a#(0(),x) -> c#(x) c#(c(x)) -> c#(b(c(x))) -> c#(c(x)) -> c#(b(c(x))) c#(c(x)) -> c#(b(c(x))) -> c#(c(b(c(x)))) -> a#(0(),c(x)) EDG Processor: DPs: c#(c(b(c(x)))) -> a#(0(),c(x)) c#(c(x)) -> c#(b(c(x))) a#(0(),x) -> c#(x) a#(0(),x) -> c#(c(x)) TRS: c(c(b(c(x)))) -> b(a(0(),c(x))) c(c(x)) -> b(c(b(c(x)))) a(0(),x) -> c(c(x)) graph: a#(0(),x) -> c#(c(x)) -> c#(c(b(c(x)))) -> a#(0(),c(x)) a#(0(),x) -> c#(c(x)) -> c#(c(x)) -> c#(b(c(x))) a#(0(),x) -> c#(x) -> c#(c(b(c(x)))) -> a#(0(),c(x)) a#(0(),x) -> c#(x) -> c#(c(x)) -> c#(b(c(x))) c#(c(b(c(x)))) -> a#(0(),c(x)) -> a#(0(),x) -> c#(x) c#(c(b(c(x)))) -> a#(0(),c(x)) -> a#(0(),x) -> c#(c(x)) SCC Processor: #sccs: 1 #rules: 3 #arcs: 6/16 DPs: a#(0(),x) -> c#(c(x)) c#(c(b(c(x)))) -> a#(0(),c(x)) a#(0(),x) -> c#(x) TRS: c(c(b(c(x)))) -> b(a(0(),c(x))) c(c(x)) -> b(c(b(c(x)))) a(0(),x) -> c(c(x)) Arctic Interpretation Processor: dimension: 1 usable rules: c(c(b(c(x)))) -> b(a(0(),c(x))) c(c(x)) -> b(c(b(c(x)))) a(0(),x) -> c(c(x)) interpretation: [c#](x0) = x0 + 0, [b](x0) = x0 + 0, [a](x0, x1) = x0 + 2x1 + 1, [a#](x0, x1) = x0 + 1x1 + 0, [c](x0) = 1x0 + 0, [0] = 1 orientation: a#(0(),x) = 1x + 1 >= 1x + 0 = c#(c(x)) c#(c(b(c(x)))) = 2x + 1 >= 2x + 1 = a#(0(),c(x)) a#(0(),x) = 1x + 1 >= x + 0 = c#(x) c(c(b(c(x)))) = 3x + 2 >= 3x + 2 = b(a(0(),c(x))) c(c(x)) = 2x + 1 >= 2x + 1 = b(c(b(c(x)))) a(0(),x) = 2x + 1 >= 2x + 1 = c(c(x)) problem: DPs: a#(0(),x) -> c#(c(x)) c#(c(b(c(x)))) -> a#(0(),c(x)) TRS: c(c(b(c(x)))) -> b(a(0(),c(x))) c(c(x)) -> b(c(b(c(x)))) a(0(),x) -> c(c(x)) Restore Modifier: DPs: a#(0(),x) -> c#(c(x)) c#(c(b(c(x)))) -> a#(0(),c(x)) TRS: c(c(b(c(x)))) -> b(a(0(),c(x))) c(c(x)) -> b(c(b(c(x)))) a(0(),x) -> c(c(x)) Semantic Labeling Processor: dimension: 2 usable rules: interpretation: [0 0] [0] [b](x0) = [0 1]x0 + [1], [1] [a](x0, x1) = x1 + [1], [0 1] [1] [c](x0) = [1 0]x0 + [0], [0] [0] = [1] labeled: a# c# b usable (for model): a# 0 c# c b a argument filtering: pi(c) = 0 pi(b) = 0 pi(0) = [] pi(a) = 0 pi(c#) = [] pi(a#) = [] precedence: c# > a# ~ a ~ 0 ~ b ~ c problem: DPs: TRS: c(c(b(c(x)))) -> b(a(0(),c(x))) c(c(x)) -> b(c(b(c(x)))) a(0(),x) -> c(c(x)) Qed