YES Problem 1: (VAR v_NonEmpty:S x:S y:S) (RULES f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) ) Problem 1: Dependency Pairs Processor: -> Pairs: F(x:S,f(a,y:S)) -> F(f(a,h(f(a,x:S))),y:S) F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) F(x:S,f(a,y:S)) -> F(a,h(f(a,x:S))) F(x:S,f(a,y:S)) -> F(a,x:S) -> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) Problem 1: SCC Processor: -> Pairs: F(x:S,f(a,y:S)) -> F(f(a,h(f(a,x:S))),y:S) F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) F(x:S,f(a,y:S)) -> F(a,h(f(a,x:S))) F(x:S,f(a,y:S)) -> F(a,x:S) -> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(x:S,f(a,y:S)) -> F(f(a,h(f(a,x:S))),y:S) F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) F(x:S,f(a,y:S)) -> F(a,x:S) ->->-> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) Problem 1: Reduction Pair Processor: -> Pairs: F(x:S,f(a,y:S)) -> F(f(a,h(f(a,x:S))),y:S) F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) F(x:S,f(a,y:S)) -> F(a,x:S) -> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) -> Usable rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X1,X2) = 2.X2 + 1 [a] = 0 [h](X) = 0 [F](X1,X2) = 2.X1 + 2.X2 Problem 1: SCC Processor: -> Pairs: F(x:S,f(a,y:S)) -> F(f(a,h(f(a,x:S))),y:S) F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) -> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(x:S,f(a,y:S)) -> F(f(a,h(f(a,x:S))),y:S) F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) ->->-> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) Problem 1: Reduction Pair Processor: -> Pairs: F(x:S,f(a,y:S)) -> F(f(a,h(f(a,x:S))),y:S) F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) -> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) -> Usable rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X1,X2) = 2.X2 + 2 [a] = 0 [h](X) = 0 [F](X1,X2) = X1 + 2.X2 Problem 1: SCC Processor: -> Pairs: F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) -> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) ->->-> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) Problem 1: Reduction Pair Processor: -> Pairs: F(x:S,f(a,y:S)) -> F(a,f(f(a,h(f(a,x:S))),y:S)) -> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) -> Usable rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) ->Interpretation type: Linear ->Coefficients: All rationals ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X1,X2) = 1/2.X1 + 2.X2 [a] = 1 [h](X) = 0 [F](X1,X2) = 1/2.X2 Problem 1: SCC Processor: -> Pairs: Empty -> Rules: f(x:S,f(a,y:S)) -> f(a,f(f(a,h(f(a,x:S))),y:S)) ->Strongly Connected Components: There is no strongly connected component The problem is finite.