MAYBE

Problem:
 strict:
  minus(x,0()) -> x
  minus(s(x),s(y)) -> minus(x,y)
  quot(0(),s(y)) -> 0()
  quot(s(x),s(y)) -> s(quot(minus(x,y),s(y)))
 weak:
  rand(x) -> x
  rand(x) -> rand(s(x))

Proof:
 Open