YES

Problem:
 strict:
  T(I(x),y) -> T(x,y)
 weak:
  T(x,y) -> T(x,I(y))

Proof:
 Matrix Interpretation Processor: dim=2
  
  interpretation:
                 [2 1]     [2 0]     [2]
   [T](x0, x1) = [0 1]x0 + [0 0]x1 + [2],
   
             [1 0]     [0]
   [I](x0) = [1 1]x0 + [1]
  orientation:
               [3 1]    [2 0]    [3]    [2 1]    [2 0]    [2]         
   T(I(x),y) = [1 1]x + [0 0]y + [3] >= [0 1]x + [0 0]y + [2] = T(x,y)
   
            [2 1]    [2 0]    [2]    [2 1]    [2 0]    [2]            
   T(x,y) = [0 1]x + [0 0]y + [2] >= [0 1]x + [0 0]y + [2] = T(x,I(y))
  problem:
   strict:
    
   weak:
    T(x,y) -> T(x,I(y))
  Qed