YES Problem: strict: R(x,B2()) -> B2() W(x,B2()) -> B2() weak: B1() -> R(T(),B1()) B1() -> W(T(),B1()) Proof: Matrix Interpretation Processor: dim=5 interpretation: [0] [0] [T] = [0] [1] [0], [1 0 0 0 0] [1 0 0 1 1] [0 0 0 0 0] [0 0 0 1 1] [R](x0, x1) = [0 0 0 1 0]x0 + [1 0 0 0 1]x1 [0 0 0 0 0] [0 0 0 0 1] [0 0 0 0 0] [1 0 0 0 0] , [0] [1] [B1] = [1] [0] [0], [1] [0] [B2] = [0] [1] [1], [1 0 0 0 0] [1 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [W](x0, x1) = [0 0 0 0 0]x0 + [0 0 1 0 1]x1 [0 0 0 0 0] [1 0 0 0 0] [0 0 0 0 0] [1 0 0 1 0] orientation: [1 0 0 0 0] [3] [1] [0 0 0 0 0] [2] [0] R(x,B2()) = [0 0 0 1 0]x + [2] >= [0] = B2() [0 0 0 0 0] [1] [1] [0 0 0 0 0] [1] [1] [1 0 0 0 0] [1] [1] [0 0 0 0 0] [0] [0] W(x,B2()) = [0 0 0 0 0]x + [1] >= [0] = B2() [0 0 0 0 0] [1] [1] [0 0 0 0 0] [2] [1] [0] [0] [1] [0] B1() = [1] >= [1] = R(T(),B1()) [0] [0] [0] [0] [0] [0] [1] [0] B1() = [1] >= [1] = W(T(),B1()) [0] [0] [0] [0] problem: strict: W(x,B2()) -> B2() weak: B1() -> R(T(),B1()) B1() -> W(T(),B1()) Matrix Interpretation Processor: dim=5 interpretation: [0] [1] [T] = [0] [0] [0], [1 0 0 0 0] [1 0 0 0 0] [0 0 0 0 0] [0 0 0 0 0] [R](x0, x1) = [0 0 0 0 0]x0 + [0 0 0 0 0]x1 [0 0 0 0 0] [0 0 0 1 0] [0 0 0 0 0] [0 0 0 1 0] , [0] [0] [B1] = [0] [1] [1], [0] [1] [B2] = [1] [0] [0], [1 0 0 0 0] [1 1 1 0 0] [0 0 0 0 0] [0 1 0 0 0] [W](x0, x1) = [0 0 0 0 0]x0 + [0 1 1 0 0]x1 [0 0 0 0 0] [0 1 1 0 0] [0 1 0 0 0] [0 0 0 0 0] orientation: [1 0 0 0 0] [2] [0] [0 0 0 0 0] [1] [1] W(x,B2()) = [0 0 0 0 0]x + [2] >= [1] = B2() [0 0 0 0 0] [2] [0] [0 1 0 0 0] [0] [0] [0] [0] [0] [0] B1() = [0] >= [0] = R(T(),B1()) [1] [1] [1] [1] [0] [0] [0] [0] B1() = [0] >= [0] = W(T(),B1()) [1] [0] [1] [1] problem: strict: weak: B1() -> R(T(),B1()) B1() -> W(T(),B1()) Qed