YES

Problem:
 strict:
  f(el(x),y) -> f(x,el(y))
 weak:
  f(x,y) -> f(l(x),y)
  f(x,y) -> f(x,r(y))
  l(el(x)) -> el(l(x))
  el(r(x)) -> r(el(x))

Proof:
 Matrix Interpretation Processor: dim=2
  
  interpretation:
                 [2 1]     [1 0]     [0]
   [f](x0, x1) = [0 0]x0 + [0 0]x1 + [2],
   
               
   [r](x0) = x0,
   
              [1 0]     [0]
   [el](x0) = [0 2]x0 + [1],
   
               
   [l](x0) = x0
  orientation:
                [2 2]    [1 0]    [1]    [2 1]    [1 0]    [0]             
   f(el(x),y) = [0 0]x + [0 0]y + [2] >= [0 0]x + [0 0]y + [2] = f(x,el(y))
   
            [2 1]    [1 0]    [0]    [2 1]    [1 0]    [0]            
   f(x,y) = [0 0]x + [0 0]y + [2] >= [0 0]x + [0 0]y + [2] = f(l(x),y)
   
            [2 1]    [1 0]    [0]    [2 1]    [1 0]    [0]            
   f(x,y) = [0 0]x + [0 0]y + [2] >= [0 0]x + [0 0]y + [2] = f(x,r(y))
   
              [1 0]    [0]    [1 0]    [0]           
   l(el(x)) = [0 2]x + [1] >= [0 2]x + [1] = el(l(x))
   
              [1 0]    [0]    [1 0]    [0]           
   el(r(x)) = [0 2]x + [1] >= [0 2]x + [1] = r(el(x))
  problem:
   strict:
    
   weak:
    f(x,y) -> f(l(x),y)
    f(x,y) -> f(x,r(y))
    l(el(x)) -> el(l(x))
    el(r(x)) -> r(el(x))
  Qed