YES After renaming modulo { n->0, s->1, o->2, p->3, t->4, c->5, m->6 }, it remains to prove termination of the 15-rule system { 0 1 -> 1 , 2 1 -> 1 , 0 2 3 -> 2 0 , 4 ->= 4 5 0 , 3 1 ->= 1 , 2 0 ->= 0 2 , 3 0 ->= 6 3 , 3 6 ->= 6 3 , 2 6 ->= 0 2 , 0 3 ->= 3 0 , 5 3 ->= 3 5 , 5 6 ->= 6 5 , 5 0 ->= 0 5 , 5 2 ->= 2 5 , 5 2 ->= 2 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 0 | | 0 1 | \ / 1 is interpreted by / \ | 1 1 | | 0 1 | \ / 2 is interpreted by / \ | 1 1 | | 0 1 | \ / 3 is interpreted by / \ | 1 1 | | 0 1 | \ / 4 is interpreted by / \ | 1 1 | | 0 1 | \ / 5 is interpreted by / \ | 1 0 | | 0 1 | \ / 6 is interpreted by / \ | 1 0 | | 0 1 | \ / After renaming modulo { 0->0, 1->1, 4->2, 5->3, 2->4, 3->5, 6->6 }, it remains to prove termination of the 12-rule system { 0 1 -> 1 , 2 ->= 2 3 0 , 4 0 ->= 0 4 , 5 0 ->= 6 5 , 5 6 ->= 6 5 , 4 6 ->= 0 4 , 0 5 ->= 5 0 , 3 5 ->= 5 3 , 3 6 ->= 6 3 , 3 0 ->= 0 3 , 3 4 ->= 4 3 , 3 4 ->= 4 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 3: 0 is interpreted by / \ | 1 0 1 | | 0 1 0 | | 0 0 1 | \ / 1 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 1 0 | \ / 2 is interpreted by / \ | 1 0 1 | | 0 1 0 | | 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / 4 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / 5 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 1 | \ / 6 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / After renaming modulo { 2->0, 3->1, 0->2, 4->3, 5->4, 6->5 }, it remains to prove termination of the 11-rule system { 0 ->= 0 1 2 , 3 2 ->= 2 3 , 4 2 ->= 5 4 , 4 5 ->= 5 4 , 3 5 ->= 2 3 , 2 4 ->= 4 2 , 1 4 ->= 4 1 , 1 5 ->= 5 1 , 1 2 ->= 2 1 , 1 3 ->= 3 1 , 1 3 ->= 3 } The system is trivially terminating.