YES
Input TRS:
      1: c(a(c(x1))) -> x1
      2: a(c(a(x1))) -> a(a(a(a(x1))))
      3: x1 ->= c(c(c(c(x1))))
Number of strict rules: 2
Direct POLO(bPol) ... failed.
Uncurrying ... failed.
Dependency Pairs:
     #1: #a(c(a(x1))) -> #a(a(a(a(x1))))
     #2: #a(c(a(x1))) -> #a(a(a(x1)))
     #3: #a(c(a(x1))) -> #a(a(x1))
     #4: #x1 ->? #c(c(c(c(x1))))
     #5: #x1 ->? #c(c(c(x1)))
     #6: #x1 ->? #c(c(x1))
     #7: #x1 ->? #c(x1)
Number of SCCs: 0, DPs: 0