YES

After renaming modulo { b->0, a->1 }, 
it remains to prove termination of the 3-rule system
{ 0 1 1 0 -> 1 1 1 1 ,
  1 0 0 1 -> 0 0 0 0 ,
  0 ->= 0 0 0 }


The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 14:

0 is interpreted by
 /                           \
| 1 0 0 0 0 0 0 0 1 0 0 0 0 0 |
| 0 1 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 0 0 1 0 1 0 0 0 0 0 0 0 0 |
| 0 0 0 0 1 0 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 1 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 1 0 0 0 0 0 0 0 0 0 1 0 1 |
| 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 0 1 0 1 0 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 0 0 0 1 0 0 0 1 0 |
| 0 0 0 0 0 0 0 0 0 0 0 0 0 1 |
| 0 0 0 0 0 0 0 0 1 0 0 0 0 0 |
 \                           /
1 is interpreted by
 /                           \
| 1 0 1 0 0 0 0 0 0 0 0 0 0 0 |
| 0 1 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 1 0 0 0 0 0 0 1 0 0 0 0 0 |
| 0 0 0 0 0 0 1 0 0 0 0 0 0 0 |
| 0 0 0 0 0 0 0 1 0 0 0 0 0 0 |
| 0 0 1 0 0 0 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 0 0 0 0 1 0 0 0 0 |
| 0 0 0 0 0 0 0 0 0 0 1 0 0 0 |
| 0 0 0 0 0 0 0 0 0 0 0 1 0 0 |
| 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
| 0 0 0 0 0 1 0 0 0 0 0 0 0 0 |
 \                           /

After renaming modulo { 0->0, 1->1 }, 
it remains to prove termination of the 2-rule system
{ 0 1 1 0 -> 1 1 1 1 ,
  0 ->= 0 0 0 }


The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 5:

0 is interpreted by
 /         \
| 1 0 1 0 0 |
| 0 1 0 0 0 |
| 0 0 0 0 0 |
| 0 0 0 0 0 |
| 0 1 0 0 0 |
 \         /
1 is interpreted by
 /         \
| 1 0 0 0 0 |
| 0 1 0 0 0 |
| 0 0 0 1 0 |
| 0 0 0 0 1 |
| 0 0 0 0 0 |
 \         /

After renaming modulo { 0->0 }, 
it remains to prove termination of the 1-rule system
{ 0 ->= 0 0 0 }

The system is trivially terminating.