YES

Problem:
 strict:
  b(a(b(x1))) -> b(a(a(a(b(x1)))))
 weak:
  a(a(a(x1))) -> b(b(b(b(x1))))

Proof:
 Bounds Processor:
  bound: 1
  enrichment: match-rt
  automaton:
   final states: {3}
   transitions:
    b0(3) -> 3*
    a0(3) -> 3*
    a1(13) -> 14*
    a1(11) -> 12*
    a1(16) -> 17*
    a1(12) -> 13*
    b1(10) -> 11*
    b1(23) -> 24*
    b1(29) -> 30*
    b1(14) -> 15*
    b1(22) -> 23*
    24 -> 14*
    17 -> 12*
    30 -> 10*
    16 -> 29*
    11 -> 14,22
    3 -> 10*
    15 -> 11,16,3
  problem:
   strict:
    
   weak:
    a(a(a(x1))) -> b(b(b(b(x1))))
  Qed