NO
proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination w.r.t. Q of the given QTRS could be disproven:

(0) QTRS
(1) NonTerminationProof [COMPLETE, 0 ms]
(2) NO


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(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   b(b(b(x1))) -> a(a(x1))
   a(a(x1)) -> b(a(b(x1)))

Q is empty.

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(1) NonTerminationProof (COMPLETE)
We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure: 
"a a b b a b b a -> b a a b b a b b a b"
a a b b a b b a -> b a a b b a b b a b
by OverlapClosure OC 2"a a b b a b b -> b a a b b a b a
by OverlapClosure OC 2"a a -> b a b
by original rule (OC 1)""b b b a b b -> a b b a b a
by OverlapClosure OC 2"b b b -> a a
by original rule (OC 1)""a a b b -> b b a b a
by OverlapClosure OC 3"a a b b -> b a a a
by OverlapClosure OC 2"a a -> b a b
by original rule (OC 1)""b b b -> a a
by original rule (OC 1)"""a a -> b a b
by original rule (OC 1)"""""a a -> b a b
by original rule (OC 1)"

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(2)
NO