YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 14 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 1 ms] (4) AND (5) QDP (6) UsableRulesProof [EQUIVALENT, 0 ms] (7) QDP (8) QDPSizeChangeProof [EQUIVALENT, 0 ms] (9) YES (10) QDP (11) QDPOrderProof [EQUIVALENT, 39 ms] (12) QDP (13) QDPOrderProof [EQUIVALENT, 2491 ms] (14) QDP (15) QDPOrderProof [EQUIVALENT, 3672 ms] (16) QDP (17) PisEmptyProof [EQUIVALENT, 0 ms] (18) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: A(a(b(b(x1)))) -> A(a(a(x1))) A(a(b(b(x1)))) -> A(a(x1)) A(a(b(b(x1)))) -> A(x1) A(c(x1)) -> C(a(x1)) A(c(x1)) -> A(x1) C(b(x1)) -> C(x1) The TRS R consists of the following rules: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 1 less node. ---------------------------------------- (4) Complex Obligation (AND) ---------------------------------------- (5) Obligation: Q DP problem: The TRS P consists of the following rules: C(b(x1)) -> C(x1) The TRS R consists of the following rules: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (6) UsableRulesProof (EQUIVALENT) We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R. ---------------------------------------- (7) Obligation: Q DP problem: The TRS P consists of the following rules: C(b(x1)) -> C(x1) R is empty. Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (8) QDPSizeChangeProof (EQUIVALENT) By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. From the DPs we obtained the following set of size-change graphs: *C(b(x1)) -> C(x1) The graph contains the following edges 1 > 1 ---------------------------------------- (9) YES ---------------------------------------- (10) Obligation: Q DP problem: The TRS P consists of the following rules: A(a(b(b(x1)))) -> A(a(x1)) A(a(b(b(x1)))) -> A(a(a(x1))) A(a(b(b(x1)))) -> A(x1) A(c(x1)) -> A(x1) The TRS R consists of the following rules: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (11) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(c(x1)) -> A(x1) The remaining pairs can at least be oriented weakly. Used ordering: Polynomial interpretation [POLO]: POL(A(x_1)) = x_1 POL(a(x_1)) = x_1 POL(b(x_1)) = x_1 POL(c(x_1)) = 1 + x_1 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) ---------------------------------------- (12) Obligation: Q DP problem: The TRS P consists of the following rules: A(a(b(b(x1)))) -> A(a(x1)) A(a(b(b(x1)))) -> A(a(a(x1))) A(a(b(b(x1)))) -> A(x1) The TRS R consists of the following rules: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (13) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(a(b(b(x1)))) -> A(a(a(x1))) A(a(b(b(x1)))) -> A(x1) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: <<< POL(A(x_1)) = [[0A]] + [[0A, -I, -I]] * x_1 >>> <<< POL(a(x_1)) = [[0A], [0A], [0A]] + [[-I, -I, 0A], [1A, -I, 0A], [0A, -I, -I]] * x_1 >>> <<< POL(b(x_1)) = [[0A], [0A], [1A]] + [[-I, -I, -I], [1A, -I, 0A], [0A, 0A, -I]] * x_1 >>> <<< POL(c(x_1)) = [[-I], [-I], [0A]] + [[0A, -I, -I], [0A, 0A, -I], [-I, -I, 0A]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) ---------------------------------------- (14) Obligation: Q DP problem: The TRS P consists of the following rules: A(a(b(b(x1)))) -> A(a(x1)) The TRS R consists of the following rules: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (15) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(a(b(b(x1)))) -> A(a(x1)) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] to (N^5, +, *, >=, >) : <<< POL(A(x_1)) = [[0]] + [[0, 1, 1, 0, 0]] * x_1 >>> <<< POL(a(x_1)) = [[0], [0], [0], [0], [0]] + [[0, 1, 0, 0, 0], [1, 0, 0, 0, 0], [1, 0, 0, 0, 0], [0, 1, 1, 0, 0], [0, 0, 0, 0, 0]] * x_1 >>> <<< POL(b(x_1)) = [[0], [0], [0], [1], [0]] + [[0, 0, 0, 1, 1], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [1, 1, 0, 0, 0], [0, 1, 0, 0, 0]] * x_1 >>> <<< POL(c(x_1)) = [[0], [0], [0], [0], [0]] + [[1, 0, 0, 0, 0], [0, 1, 0, 0, 0], [0, 0, 1, 0, 0], [0, 0, 0, 1, 0], [0, 0, 0, 0, 1]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) ---------------------------------------- (16) Obligation: Q DP problem: P is empty. The TRS R consists of the following rules: a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) a(c(x1)) -> c(a(x1)) c(b(x1)) -> b(c(x1)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (17) PisEmptyProof (EQUIVALENT) The TRS P is empty. Hence, there is no (P,Q,R) chain. ---------------------------------------- (18) YES