YES After renaming modulo { a->0, b->1, c->2, d->3 }, it remains to prove termination of the 4-rule system { 0 0 -> 1 1 , 2 2 1 -> 3 2 0 , 0 -> 3 2 2 , 2 3 -> 1 2 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 3: 0 is interpreted by / \ | 1 0 1 | | 0 1 0 | | 0 1 0 | \ / 1 is interpreted by / \ | 1 0 1 | | 0 1 0 | | 0 0 0 | \ / 2 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / After renaming modulo { 2->0, 1->1, 3->2, 0->3 }, it remains to prove termination of the 3-rule system { 0 0 1 -> 2 0 3 , 3 -> 2 0 0 , 0 2 -> 1 0 } The system was reversed. After renaming modulo { 1->0, 0->1, 3->2, 2->3 }, it remains to prove termination of the 3-rule system { 0 1 1 -> 2 1 3 , 2 -> 1 1 3 , 3 1 -> 1 0 } Applying the dependency pairs transformation. After renaming modulo { (0,true)->0, (1,false)->1, (2,true)->2, (3,false)->3, (3,true)->4, (0,false)->5, (2,false)->6 }, it remains to prove termination of the 7-rule system { 0 1 1 -> 2 1 3 , 0 1 1 -> 4 , 2 -> 4 , 4 1 -> 0 , 5 1 1 ->= 6 1 3 , 6 ->= 1 1 3 , 3 1 ->= 1 5 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 5: 0 is interpreted by / \ | 1 0 1 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 1 0 | | 0 1 0 0 1 | | 0 0 1 0 0 | \ / 2 is interpreted by / \ | 1 0 0 0 1 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 1 | | 0 1 0 0 1 | | 0 0 0 0 1 | \ / 4 is interpreted by / \ | 1 0 0 0 1 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 5 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 1 0 0 | | 0 0 1 0 0 | | 0 0 1 0 0 | \ / 6 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 1 0 0 1 | | 0 1 0 0 1 | | 0 1 0 0 1 | \ / After renaming modulo { 2->0, 4->1, 1->2, 0->3, 5->4, 6->5, 3->6 }, it remains to prove termination of the 5-rule system { 0 -> 1 , 1 2 -> 3 , 4 2 2 ->= 5 2 6 , 5 ->= 2 2 6 , 6 2 ->= 2 4 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 0 | | 0 1 | \ / 3 is interpreted by / \ | 1 0 | | 0 1 | \ / 4 is interpreted by / \ | 1 0 | | 0 1 | \ / 5 is interpreted by / \ | 1 0 | | 0 1 | \ / 6 is interpreted by / \ | 1 0 | | 0 1 | \ / After renaming modulo { 1->0, 2->1, 3->2, 4->3, 5->4, 6->5 }, it remains to prove termination of the 4-rule system { 0 1 -> 2 , 3 1 1 ->= 4 1 5 , 4 ->= 1 1 5 , 5 1 ->= 1 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 0 | | 0 1 | \ / 3 is interpreted by / \ | 1 0 | | 0 1 | \ / 4 is interpreted by / \ | 1 0 | | 0 1 | \ / 5 is interpreted by / \ | 1 0 | | 0 1 | \ / After renaming modulo { 3->0, 1->1, 4->2, 5->3 }, it remains to prove termination of the 3-rule system { 0 1 1 ->= 2 1 3 , 2 ->= 1 1 3 , 3 1 ->= 1 0 } The system is trivially terminating.