NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 719 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(b(x1))) -> b(c(b(a(a(a(x1)))))) a(c(x1)) -> b(x1) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a a b a b c b -> b c b b c b b c b a b c b a b c b b c b a a a b a b c b a a a" a a b a b c b -> b c b b c b b c b a b c b a b c b b c b a a a b a b c b a a a by OverlapClosure OC 3"a a b a b c b -> b c b b c b b c b a b c b a b c b a a b b a b c b a a a by OverlapClosure OC 2"a a b a b c -> b c b b c b b c b a b c b a b c b a a b b a a a by OverlapClosure OC 3"a a b a b c -> b c b b c b b c b a b c b a a a b c b a a a by OverlapClosure OC 3"a a b a b c -> b c b b c b b c b a a a b b c b a a a by OverlapClosure OC 3"a a b a b c -> b c b b c b a a b b b c b a a a by OverlapClosure OC 3"a a b a b c -> b c b b c b a a a c b b c b a a a by OverlapClosure OC 3"a a b a b c -> b c b a a b c b b c b a a a by OverlapClosure OC 2"a a b a b c -> b c b a a b c b a a b by OverlapClosure OC 2"a a b -> b c b a a a by original rule (OC 1)""a a b c -> b c b a a b by OverlapClosure OC 2"a a b -> b c b a a a by original rule (OC 1)""a c -> b by original rule (OC 1)""""a a b -> b c b a a a by original rule (OC 1)"""a a b -> b c b a a a by original rule (OC 1)"""a c -> b by original rule (OC 1)"""a a b -> b c b a a a by original rule (OC 1)"""a a b -> b c b a a a by original rule (OC 1)"""a a b c -> b c b a a b by OverlapClosure OC 2"a a b -> b c b a a a by original rule (OC 1)""a c -> b by original rule (OC 1)""""a a b -> b c b a a a by original rule (OC 1)"""a a b -> b c b a a a by original rule (OC 1)" ---------------------------------------- (2) NO