MAYBE

Problem:
 b(a(b(b(x1)))) -> b(b(b(a(b(x1)))))
 b(a(a(b(b(x1))))) -> b(a(b(b(a(a(b(x1)))))))
 b(a(a(a(b(b(x1)))))) -> b(a(a(b(b(a(a(a(b(x1)))))))))
 b(a(a(a(a(b(b(x1))))))) -> b(a(a(a(b(b(a(a(a(a(b(x1)))))))))))

Proof:
 Open