NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 510 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(x1))) -> c(c(b(x1))) b(b(b(x1))) -> c(c(c(x1))) c(c(c(x1))) -> a(b(b(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a a a b b b b -> a a a b b b b" a a a b b b b -> a a a b b b b by OverlapClosure OC 3"a a a b b b b -> a a c c c b b by OverlapClosure OC 3"a a a b b b b -> a a b b b b b by OverlapClosure OC 3"a a a b b b b -> a b b b b b b by OverlapClosure OC 3"a a a b b b b -> c c c b b b b by OverlapClosure OC 3"a a a b b b b -> c a a a b b b by OverlapClosure OC 3"a a a b b b b -> c a a b b b b by OverlapClosure OC 3"a a a b b b b -> c a b b b b b by OverlapClosure OC 3"a a a b b b b -> c c c c b b b by OverlapClosure OC 2"a a a -> c c b by original rule (OC 1)""b b b b b -> c c b b b by OverlapClosure OC 2"b b b -> c c c by original rule (OC 1)""c c c b b -> c c b b b by OverlapClosure OC 3"c c c b b -> a a a b b by OverlapClosure OC 2"c c c -> a b b by original rule (OC 1)""b b b b -> a a b b by OverlapClosure OC 2"b b b -> a b b by OverlapClosure OC 2"b b b -> c c c by original rule (OC 1)""c c c -> a b b by original rule (OC 1)"""b b b -> a b b by OverlapClosure OC 2"b b b -> c c c by original rule (OC 1)""c c c -> a b b by original rule (OC 1)"""""a a a -> c c b by original rule (OC 1)"""""c c c -> a b b by original rule (OC 1)"""b b b -> a b b by OverlapClosure OC 2"b b b -> c c c by original rule (OC 1)""c c c -> a b b by original rule (OC 1)""""b b b -> a b b by OverlapClosure OC 2"b b b -> c c c by original rule (OC 1)""c c c -> a b b by original rule (OC 1)""""a a a -> c c b by original rule (OC 1)"""c c c -> a b b by original rule (OC 1)"""b b b -> a b b by OverlapClosure OC 2"b b b -> c c c by original rule (OC 1)""c c c -> a b b by original rule (OC 1)""""b b b -> c c c by original rule (OC 1)"""c c c -> a b b by original rule (OC 1)" ---------------------------------------- (2) NO