YES Problem 1: (VAR v_NonEmpty:S x1:S) (RULES 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ) Problem 1: Dependency Pairs Processor: -> Pairs: 0#(q1(x1:S)) -> 1#(x1:S) 1#(q0(0(x1:S))) -> 0#(0(q1(x1:S))) 1#(q0(0(x1:S))) -> 0#(q1(x1:S)) 1#(q0(1(x1:S))) -> 0#(1(q1(x1:S))) 1#(q0(1(x1:S))) -> 1#(q1(x1:S)) 1#(q1(0(x1:S))) -> 0#(q1(x1:S)) 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) Problem 1: SCC Processor: -> Pairs: 0#(q1(x1:S)) -> 1#(x1:S) 1#(q0(0(x1:S))) -> 0#(0(q1(x1:S))) 1#(q0(0(x1:S))) -> 0#(q1(x1:S)) 1#(q0(1(x1:S))) -> 0#(1(q1(x1:S))) 1#(q0(1(x1:S))) -> 1#(q1(x1:S)) 1#(q1(0(x1:S))) -> 0#(q1(x1:S)) 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: 0#(q1(x1:S)) -> 1#(x1:S) 1#(q0(0(x1:S))) -> 0#(0(q1(x1:S))) 1#(q0(0(x1:S))) -> 0#(q1(x1:S)) 1#(q0(1(x1:S))) -> 0#(1(q1(x1:S))) 1#(q0(1(x1:S))) -> 1#(q1(x1:S)) 1#(q1(0(x1:S))) -> 0#(q1(x1:S)) 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) ->->-> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) Problem 1: Reduction Pair Processor: -> Pairs: 0#(q1(x1:S)) -> 1#(x1:S) 1#(q0(0(x1:S))) -> 0#(0(q1(x1:S))) 1#(q0(0(x1:S))) -> 0#(q1(x1:S)) 1#(q0(1(x1:S))) -> 0#(1(q1(x1:S))) 1#(q0(1(x1:S))) -> 1#(q1(x1:S)) 1#(q1(0(x1:S))) -> 0#(q1(x1:S)) 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) -> Usable rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [0](X) = 2.X + 2 [1](X) = 2.X + 1 [q0](X) = 2.X + 2 [q1](X) = 2.X + 1 [q2](X) = 2.X + 2 [0#](X) = X + 2 [1#](X) = 2.X + 2 Problem 1: SCC Processor: -> Pairs: 1#(q0(0(x1:S))) -> 0#(0(q1(x1:S))) 1#(q0(0(x1:S))) -> 0#(q1(x1:S)) 1#(q0(1(x1:S))) -> 0#(1(q1(x1:S))) 1#(q0(1(x1:S))) -> 1#(q1(x1:S)) 1#(q1(0(x1:S))) -> 0#(q1(x1:S)) 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: 1#(q0(1(x1:S))) -> 1#(q1(x1:S)) 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) ->->-> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) Problem 1: Reduction Pair Processor: -> Pairs: 1#(q0(1(x1:S))) -> 1#(q1(x1:S)) 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) -> Usable rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [0](X) = 2.X + 1 [1](X) = 2.X [q0](X) = 2.X + 1 [q1](X) = 2.X [q2](X) = 2.X + 1 [1#](X) = X Problem 1: SCC Processor: -> Pairs: 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) ->->-> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) Problem 1: Reduction Pair Processor: -> Pairs: 1#(q1(0(x1:S))) -> 1#(0(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) -> Usable rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [0](X) = 2.X + 2 [1](X) = 2.X [q0](X) = 2.X + 2 [q1](X) = 2.X [q2](X) = 2.X + 2 [1#](X) = X Problem 1: SCC Processor: -> Pairs: 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) ->->-> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) Problem 1: Reduction Pair Processor: -> Pairs: 1#(q1(1(x1:S))) -> 1#(1(q1(x1:S))) 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) -> Usable rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [0](X) = X + 2 [1](X) = 2.X + 2 [q0](X) = X + 1 [q1](X) = 2.X + 1 [q2](X) = X + 1 [1#](X) = 2.X Problem 1: SCC Processor: -> Pairs: 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) ->->-> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->->Cycle: ->->-> Pairs: 1#(q2(x1:S)) -> 1#(x1:S) ->->-> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) The problem is decomposed in 2 subproblems. Problem 1.1: Reduction Pair Processor: -> Pairs: 1#(q1(1(x1:S))) -> 1#(q1(x1:S)) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) -> Usable rules: Empty ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [1](X) = 2.X + 2 [q1](X) = 2.X [1#](X) = 2.X Problem 1.1: SCC Processor: -> Pairs: Empty -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: Subterm Processor: -> Pairs: 1#(q2(x1:S)) -> 1#(x1:S) -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Projection: pi(1#) = 1 Problem 1.2: SCC Processor: -> Pairs: Empty -> Rules: 0(q1(x1:S)) -> q2(1(x1:S)) 0(q2(x1:S)) -> 0(q0(x1:S)) 1(q0(0(x1:S))) -> 0(0(q1(x1:S))) 1(q0(1(x1:S))) -> 0(1(q1(x1:S))) 1(q1(0(x1:S))) -> 1(0(q1(x1:S))) 1(q1(1(x1:S))) -> 1(1(q1(x1:S))) 1(q2(x1:S)) -> q2(1(x1:S)) ->Strongly Connected Components: There is no strongly connected component The problem is finite.