NO
proof of /export/starexec/sandbox/benchmark/theBenchmark.xml
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination w.r.t. Q of the given QTRS could be disproven:

(0) QTRS
(1) NonTerminationProof [COMPLETE, 0 ms]
(2) NO


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(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   a(x1) -> x1
   a(b(x1)) -> a(a(c(b(b(a(x1))))))
   b(x1) -> x1
   c(c(x1)) -> x1

Q is empty.

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(1) NonTerminationProof (COMPLETE)
We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure: 
"a b b -> a a b b a"
a b b -> a a b b a
by OverlapClosure OC 3"a b b -> a a c c b b a
by OverlapClosure OC 2"a b -> a a c a
by OverlapClosure OC 3"a b -> a a c b a
by OverlapClosure OC 3"a b -> a a c b b a
by original rule (OC 1)""b -> 
by original rule (OC 1)"""b -> 
by original rule (OC 1)"""a b -> c b b a
by OverlapClosure OC 3"a b -> a c b b a
by OverlapClosure OC 3"a b -> a a c b b a
by original rule (OC 1)""a -> 
by original rule (OC 1)"""a -> 
by original rule (OC 1)""""c c -> 
by original rule (OC 1)"

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(2)
NO