NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 3863 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> x1 a(a(x1)) -> b(b(c(x1))) b(x1) -> x1 c(b(x1)) -> b(a(c(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "c b b b b b b -> b c b b b b b b c c c" c b b b b b b -> b c b b b b b b c c c by OverlapClosure OC 2"c b b -> b c c by OverlapClosure OC 3"c b b -> a a c by OverlapClosure OC 2"c b -> a c by OverlapClosure OC 3"c b -> b a c by original rule (OC 1)""b -> by original rule (OC 1)"""c b -> a c by OverlapClosure OC 3"c b -> b a c by original rule (OC 1)""b -> by original rule (OC 1)""""a a -> b c by OverlapClosure OC 3"a a -> b b c by original rule (OC 1)""b -> by original rule (OC 1)""""c b b b b -> b b b b b b c c c by OverlapClosure OC 3"c b b b b -> b b b b a a c c by OverlapClosure OC 3"c b b b b -> b b b b a c b c by OverlapClosure OC 2"c b b b -> b b b b a c c by OverlapClosure OC 3"c b b b -> b b b c b c by OverlapClosure OC 2"c b b -> b b b c c by OverlapClosure OC 3"c b b -> b a a c by OverlapClosure OC 2"c b -> b a c by original rule (OC 1)""c b -> a c by OverlapClosure OC 3"c b -> b a c by original rule (OC 1)""b -> by original rule (OC 1)""""a a -> b b c by original rule (OC 1)"""c b -> b c by OverlapClosure OC 3"c b -> b a c by original rule (OC 1)""a -> by original rule (OC 1)""""c b -> b a c by original rule (OC 1)"""c b -> b c by OverlapClosure OC 3"c b -> b a c by original rule (OC 1)""a -> by original rule (OC 1)""""c b -> a c by OverlapClosure OC 3"c b -> b a c by original rule (OC 1)""b -> by original rule (OC 1)""""a a -> b b c by original rule (OC 1)"" ---------------------------------------- (2) NO