NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 3146 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(x1)) -> b(x1) a(b(c(x1))) -> c(c(a(a(a(a(x1)))))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a b c b c c a c c -> c c c c a c c b c c a a b c b c c a c c a a a a" a b c b c c a c c -> c c c c a c c b c c a a b c b c c a c c a a a a by OverlapClosure OC 2"a b c b c c a c -> c c c c a c c b c c a a b c b c c a a b by OverlapClosure OC 2"a b c b c c a -> c c c c a c c b c c a a b c b a b by OverlapClosure OC 3"a b c b c c a -> c c c c a c c b c c a a a a c b a b by OverlapClosure OC 3"a b c b c c a -> c c c c a c c b a b c c b a b by OverlapClosure OC 2"a b c b c c -> c c c c a c c b a b c c b a a by OverlapClosure OC 2"a b c b c -> c c c c a c c b a b a b by OverlapClosure OC 3"a b c b c -> c c c c a a b c a a b by OverlapClosure OC 3"a b c b c -> c c c c a a a a c a a b by OverlapClosure OC 3"a b c b c -> c c a b c c a a b by OverlapClosure OC 2"a b c -> c c a b a by OverlapClosure OC 3"a b c -> c c a a a a by original rule (OC 1)""a a -> b by original rule (OC 1)"""a b c -> c c a a b by OverlapClosure OC 2"a b c -> c c a a a a by original rule (OC 1)""a a -> b by original rule (OC 1)""""a b c -> c c a a a a by original rule (OC 1)"""a a -> b by original rule (OC 1)"""a b c a -> c c b a b by OverlapClosure OC 3"a b c a -> c c a a a b by OverlapClosure OC 2"a b c -> c c a a a a by original rule (OC 1)""a a -> b by original rule (OC 1)"""a a -> b by original rule (OC 1)""""a b c -> c c b a a by OverlapClosure OC 3"a b c -> c c a a a a by original rule (OC 1)""a a -> b by original rule (OC 1)""""a a -> b by original rule (OC 1)"""a b c -> c c a a a a by original rule (OC 1)"""a a -> b by original rule (OC 1)"""a b c -> c c a a b by OverlapClosure OC 2"a b c -> c c a a a a by original rule (OC 1)""a a -> b by original rule (OC 1)""""a b c -> c c a a a a by original rule (OC 1)" ---------------------------------------- (2) NO