NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 2295 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> x1 a(b(b(x1))) -> b(b(b(a(c(a(x1)))))) c(b(x1)) -> x1 Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a b b b b b b b b -> b b b a b b b b b b b b c c c" a b b b b b b b b -> b b b a b b b b b b b b c c c by OverlapClosure OC 3"a b b b b b b b b -> b b b a c b b b b b b b b b c c c by OverlapClosure OC 3"a b b b b b b b b -> b b b a c b b b b b b b b b a c c c by OverlapClosure OC 2"a b b -> b b b a c a by original rule (OC 1)""a b b b b b b -> b b b b b b b b b a c c c by OverlapClosure OC 3"a b b b b b b -> b b b b b b a b b c c by OverlapClosure OC 3"a b b b b b b -> b b b a b b b b b c c by OverlapClosure OC 3"a b b b b b b -> b b b a c b b b b b b c c by OverlapClosure OC 3"a b b b b b b -> b b b a c b b b b b b a c c by OverlapClosure OC 2"a b b -> b b b a c a by original rule (OC 1)""a b b b b -> b b b b b b a c c by OverlapClosure OC 3"a b b b b -> b b b a b b c by OverlapClosure OC 3"a b b b b -> b b b a c b b b c by OverlapClosure OC 3"a b b b b -> b b b a c b b b a c by OverlapClosure OC 2"a b b -> b b b a c a by original rule (OC 1)""a b b -> b b b a c by OverlapClosure OC 2"a b b -> b b b a c a by original rule (OC 1)""a -> by original rule (OC 1)""""a -> by original rule (OC 1)"""c b -> by original rule (OC 1)"""a b b -> b b b a c by OverlapClosure OC 2"a b b -> b b b a c a by original rule (OC 1)""a -> by original rule (OC 1)"""""a -> by original rule (OC 1)"""c b -> by original rule (OC 1)"""a b b b -> b b b a by OverlapClosure OC 2"a b b -> b b b a c by OverlapClosure OC 2"a b b -> b b b a c a by original rule (OC 1)""a -> by original rule (OC 1)"""c b -> by original rule (OC 1)""""a b b -> b b b a c by OverlapClosure OC 2"a b b -> b b b a c a by original rule (OC 1)""a -> by original rule (OC 1)"""""a -> by original rule (OC 1)"""c b -> by original rule (OC 1)" ---------------------------------------- (2) NO