YES
proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination w.r.t. Q of the given QTRS could be proven:

(0) QTRS
(1) DependencyPairsProof [EQUIVALENT, 9 ms]
(2) QDP
(3) QDPOrderProof [EQUIVALENT, 195 ms]
(4) QDP
(5) DependencyGraphProof [EQUIVALENT, 0 ms]
(6) TRUE


----------------------------------------

(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   a(x1) -> x1
   a(a(b(a(x1)))) -> b(b(a(a(a(x1)))))
   b(x1) -> a(x1)

Q is empty.

----------------------------------------

(1) DependencyPairsProof (EQUIVALENT)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
----------------------------------------

(2)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   A(a(b(a(x1)))) -> B(b(a(a(a(x1)))))
   A(a(b(a(x1)))) -> B(a(a(a(x1))))
   A(a(b(a(x1)))) -> A(a(a(x1)))
   A(a(b(a(x1)))) -> A(a(x1))
   B(x1) -> A(x1)

The TRS R consists of the following rules:

   a(x1) -> x1
   a(a(b(a(x1)))) -> b(b(a(a(a(x1)))))
   b(x1) -> a(x1)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.
----------------------------------------

(3) QDPOrderProof (EQUIVALENT)
We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.

   A(a(b(a(x1)))) -> B(b(a(a(a(x1)))))
   A(a(b(a(x1)))) -> B(a(a(a(x1))))
   A(a(b(a(x1)))) -> A(a(a(x1)))
   A(a(b(a(x1)))) -> A(a(x1))
The remaining pairs can at least be oriented weakly.
Used ordering:  Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

   <<<
 POL(A(x_1)) =  	[[0A]] 	 +  	[[-I, -I, 0A]] 	* 	x_1
>>>

   <<<
 POL(a(x_1)) =  	[[-I], [0A], [-I]] 	 +  	[[0A, -I, 0A], [0A, 0A, 0A], [0A, -I, 0A]] 	* 	x_1
>>>

   <<<
 POL(b(x_1)) =  	[[1A], [0A], [-I]] 	 +  	[[0A, 0A, 1A], [0A, 0A, 0A], [0A, -I, 0A]] 	* 	x_1
>>>

   <<<
 POL(B(x_1)) =  	[[0A]] 	 +  	[[-I, -I, 0A]] 	* 	x_1
>>>


The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

   a(x1) -> x1
   a(a(b(a(x1)))) -> b(b(a(a(a(x1)))))
   b(x1) -> a(x1)


----------------------------------------

(4)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   B(x1) -> A(x1)

The TRS R consists of the following rules:

   a(x1) -> x1
   a(a(b(a(x1)))) -> b(b(a(a(a(x1)))))
   b(x1) -> a(x1)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.
----------------------------------------

(5) DependencyGraphProof (EQUIVALENT)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node.
----------------------------------------

(6)
TRUE