YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 131 ms] (6) QDP (7) DependencyGraphProof [EQUIVALENT, 0 ms] (8) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> x1 a(b(x1)) -> c(b(b(x1))) b(x1) -> a(a(c(x1))) c(c(x1)) -> x1 Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: A(b(x1)) -> C(b(b(x1))) A(b(x1)) -> B(b(x1)) B(x1) -> A(a(c(x1))) B(x1) -> A(c(x1)) B(x1) -> C(x1) The TRS R consists of the following rules: a(x1) -> x1 a(b(x1)) -> c(b(b(x1))) b(x1) -> a(a(c(x1))) c(c(x1)) -> x1 Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: A(b(x1)) -> B(b(x1)) B(x1) -> A(a(c(x1))) B(x1) -> A(c(x1)) The TRS R consists of the following rules: a(x1) -> x1 a(b(x1)) -> c(b(b(x1))) b(x1) -> a(a(c(x1))) c(c(x1)) -> x1 Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. B(x1) -> A(a(c(x1))) B(x1) -> A(c(x1)) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic integers [ARCTIC,STERNAGEL_THIEMANN_RTA14]: <<< POL(A(x_1)) = [[0A]] + [[-I, -1A, -I]] * x_1 >>> <<< POL(b(x_1)) = [[0A], [2A], [1A]] + [[0A, 0A, 0A], [-1A, 1A, 1A], [-1A, 1A, 1A]] * x_1 >>> <<< POL(B(x_1)) = [[1A]] + [[-I, -I, -1A]] * x_1 >>> <<< POL(a(x_1)) = [[-1A], [-1A], [-1A]] + [[0A, 0A, -1A], [-I, 0A, -I], [-I, 2A, 0A]] * x_1 >>> <<< POL(c(x_1)) = [[-1A], [-1A], [-1A]] + [[0A, -1A, -I], [-I, -I, -1A], [-1A, 1A, -1A]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: b(x1) -> a(a(c(x1))) c(c(x1)) -> x1 a(x1) -> x1 a(b(x1)) -> c(b(b(x1))) ---------------------------------------- (6) Obligation: Q DP problem: The TRS P consists of the following rules: A(b(x1)) -> B(b(x1)) The TRS R consists of the following rules: a(x1) -> x1 a(b(x1)) -> c(b(b(x1))) b(x1) -> a(a(c(x1))) c(c(x1)) -> x1 Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (7) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node. ---------------------------------------- (8) TRUE