YES Problem: a(x1) -> b(x1) b(a(c(x1))) -> c(c(b(a(a(x1))))) c(b(x1)) -> x1 Proof: String Reversal Processor: a(x1) -> b(x1) c(a(b(x1))) -> a(a(b(c(c(x1))))) b(c(x1)) -> x1 DP Processor: DPs: a#(x1) -> b#(x1) c#(a(b(x1))) -> c#(x1) c#(a(b(x1))) -> c#(c(x1)) c#(a(b(x1))) -> b#(c(c(x1))) c#(a(b(x1))) -> a#(b(c(c(x1)))) c#(a(b(x1))) -> a#(a(b(c(c(x1))))) TRS: a(x1) -> b(x1) c(a(b(x1))) -> a(a(b(c(c(x1))))) b(c(x1)) -> x1 TDG Processor: DPs: a#(x1) -> b#(x1) c#(a(b(x1))) -> c#(x1) c#(a(b(x1))) -> c#(c(x1)) c#(a(b(x1))) -> b#(c(c(x1))) c#(a(b(x1))) -> a#(b(c(c(x1)))) c#(a(b(x1))) -> a#(a(b(c(c(x1))))) TRS: a(x1) -> b(x1) c(a(b(x1))) -> a(a(b(c(c(x1))))) b(c(x1)) -> x1 graph: c#(a(b(x1))) -> c#(c(x1)) -> c#(a(b(x1))) -> a#(a(b(c(c(x1))))) c#(a(b(x1))) -> c#(c(x1)) -> c#(a(b(x1))) -> a#(b(c(c(x1)))) c#(a(b(x1))) -> c#(c(x1)) -> c#(a(b(x1))) -> b#(c(c(x1))) c#(a(b(x1))) -> c#(c(x1)) -> c#(a(b(x1))) -> c#(c(x1)) c#(a(b(x1))) -> c#(c(x1)) -> c#(a(b(x1))) -> c#(x1) c#(a(b(x1))) -> c#(x1) -> c#(a(b(x1))) -> a#(a(b(c(c(x1))))) c#(a(b(x1))) -> c#(x1) -> c#(a(b(x1))) -> a#(b(c(c(x1)))) c#(a(b(x1))) -> c#(x1) -> c#(a(b(x1))) -> b#(c(c(x1))) c#(a(b(x1))) -> c#(x1) -> c#(a(b(x1))) -> c#(c(x1)) c#(a(b(x1))) -> c#(x1) -> c#(a(b(x1))) -> c#(x1) c#(a(b(x1))) -> a#(b(c(c(x1)))) -> a#(x1) -> b#(x1) c#(a(b(x1))) -> a#(a(b(c(c(x1))))) -> a#(x1) -> b#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 12/36 DPs: c#(a(b(x1))) -> c#(c(x1)) c#(a(b(x1))) -> c#(x1) TRS: a(x1) -> b(x1) c(a(b(x1))) -> a(a(b(c(c(x1))))) b(c(x1)) -> x1 Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> b(x1) c(a(b(x1))) -> a(a(b(c(c(x1))))) b(c(x1)) -> x1 interpretation: [0 0] [b](x0) = [0 0]x0, [c#](x0) = [0 2]x0 + [0], [0 0] [-&] [a](x0) = [1 0]x0 + [0 ], [0 0] [c](x0) = [0 0]x0 orientation: c#(a(b(x1))) = [3 3]x1 + [2] >= [2 2]x1 + [0] = c#(c(x1)) c#(a(b(x1))) = [3 3]x1 + [2] >= [0 2]x1 + [0] = c#(x1) [0 0] [-&] [0 0] a(x1) = [1 0]x1 + [0 ] >= [0 0]x1 = b(x1) [1 1] [0] [1 1] [0] c(a(b(x1))) = [1 1]x1 + [0] >= [1 1]x1 + [0] = a(a(b(c(c(x1))))) [0 0] b(c(x1)) = [0 0]x1 >= x1 = x1 problem: DPs: TRS: a(x1) -> b(x1) c(a(b(x1))) -> a(a(b(c(c(x1))))) b(c(x1)) -> x1 Qed