NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 14.1 s] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> x1 a(a(x1)) -> b(a(b(c(x1)))) c(x1) -> x1 c(b(x1)) -> a(c(x1)) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "c b b b b b a b -> b b c b b b b b a b c" c b b b b b a b -> b b c b b b b b a b c by OverlapClosure OC 2"c b b b b b a b -> b b c b b b b a a by OverlapClosure OC 2"c b b -> b b c c by OverlapClosure OC 3"c b b -> b a b c c by OverlapClosure OC 3"c b b -> a a c by OverlapClosure OC 2"c b -> a c by original rule (OC 1)""c b -> a c by original rule (OC 1)"""a a -> b a b c by original rule (OC 1)"""a -> by original rule (OC 1)"""c b b b a b -> b b b b a a by OverlapClosure OC 2"c b b b a -> b b b b a c by OverlapClosure OC 3"c b b b a -> b b b a b a c by OverlapClosure OC 2"c b b b a -> b b b a b c b by OverlapClosure OC 3"c b b b a -> b b a a b by OverlapClosure OC 3"c b b b a -> b b a c a b by OverlapClosure OC 3"c b b b a -> b b c b a b by OverlapClosure OC 2"c b b -> b b c c by OverlapClosure OC 3"c b b -> b a b c c by OverlapClosure OC 3"c b b -> a a c by OverlapClosure OC 2"c b -> a c by original rule (OC 1)""c b -> a c by original rule (OC 1)"""a a -> b a b c by original rule (OC 1)"""a -> by original rule (OC 1)"""c b a -> b a b by OverlapClosure OC 2"c b -> a by OverlapClosure OC 2"c b -> a c by original rule (OC 1)""c -> by original rule (OC 1)"""a a -> b a b by OverlapClosure OC 2"a a -> b a b c by original rule (OC 1)""c -> by original rule (OC 1)"""""c b -> a c by original rule (OC 1)"""c -> by original rule (OC 1)"""a a -> b a b c by original rule (OC 1)"""c b -> a c by original rule (OC 1)"""a -> by original rule (OC 1)"""c b -> a by OverlapClosure OC 2"c b -> a c by original rule (OC 1)""c -> by original rule (OC 1)"""""a a -> b a b c by original rule (OC 1)" ---------------------------------------- (2) NO