NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 738 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> b(c(x1)) a(b(b(x1))) -> c(a(a(a(x1)))) c(c(x1)) -> x1 Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a b b b b c b c b -> c a b b b b c b c b c" a b b b b c b c b -> c a b b b b c b c b c by OverlapClosure OC 2"a b b b b c b c b -> c a b b b b c b c a by OverlapClosure OC 3"a b b b b c b c b -> c a b b b b c a a by OverlapClosure OC 3"a b b b b c b c b -> c a b b b a a a by OverlapClosure OC 3"a b b b b c b c b -> c a a c b b a a a by OverlapClosure OC 2"a b b -> c a a a by original rule (OC 1)""a b b c b c b -> c b b a a a by OverlapClosure OC 3"a b b c b c b -> c a c b a a a by OverlapClosure OC 2"a b b c -> c a a b by OverlapClosure OC 2"a b b -> c a a a by original rule (OC 1)""a c -> b by OverlapClosure OC 2"a -> b c by original rule (OC 1)""c c -> by original rule (OC 1)""""a b b c b -> c b a a a by OverlapClosure OC 3"a b b c b -> c a c a a a by OverlapClosure OC 2"a b b c -> c a a b by OverlapClosure OC 2"a b b -> c a a a by original rule (OC 1)""a c -> b by OverlapClosure OC 2"a -> b c by original rule (OC 1)""c c -> by original rule (OC 1)""""a b b -> c a a a by original rule (OC 1)"""a c -> b by OverlapClosure OC 2"a -> b c by original rule (OC 1)""c c -> by original rule (OC 1)"""""a c -> b by OverlapClosure OC 2"a -> b c by original rule (OC 1)""c c -> by original rule (OC 1)"""""a c -> b by OverlapClosure OC 2"a -> b c by original rule (OC 1)""c c -> by original rule (OC 1)""""a -> b c by original rule (OC 1)"""a -> b c by original rule (OC 1)"""a -> b c by original rule (OC 1)" ---------------------------------------- (2) NO