NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 460 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(x1)) -> b(x1) a(b(x1)) -> c(a(x1)) c(c(x1)) -> b(a(b(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a b b b b a b b -> b a b b b b a b b b a" a b b b b a b b -> b a b b b b a b b b a by OverlapClosure OC 2"a b b -> b a b a by OverlapClosure OC 3"a b b -> c c a by OverlapClosure OC 2"a b -> c a by original rule (OC 1)""a b -> c a by original rule (OC 1)"""c c -> b a b by original rule (OC 1)"""a b b a b b -> b b b a b b b a by OverlapClosure OC 3"a b b a b b -> b b c c b b a by OverlapClosure OC 3"a b b a b b -> b b c c a a b a by OverlapClosure OC 3"a b b a b b -> b b c a b a b a by OverlapClosure OC 2"a b b a -> b b c a a by OverlapClosure OC 3"a b b a -> b c c a by OverlapClosure OC 2"a b b a -> b c a b by OverlapClosure OC 2"a b b -> b c a a by OverlapClosure OC 3"a b b -> c c a by OverlapClosure OC 2"a b -> c a by original rule (OC 1)""a b -> c a by original rule (OC 1)"""c c -> b c a by OverlapClosure OC 2"c c -> b a b by original rule (OC 1)""a b -> c a by original rule (OC 1)""""a a -> b by original rule (OC 1)"""a b -> c a by original rule (OC 1)"""c c -> b c a by OverlapClosure OC 2"c c -> b a b by original rule (OC 1)""a b -> c a by original rule (OC 1)""""a b b -> b a b a by OverlapClosure OC 3"a b b -> c c a by OverlapClosure OC 2"a b -> c a by original rule (OC 1)""a b -> c a by original rule (OC 1)"""c c -> b a b by original rule (OC 1)""""a b -> c a by original rule (OC 1)"""a a -> b by original rule (OC 1)"""c c -> b a b by original rule (OC 1)"" ---------------------------------------- (2) NO