YES Problem: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 Proof: DP Processor: DPs: a#(x1) -> c#(x1) a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 TDG Processor: DPs: a#(x1) -> c#(x1) a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 graph: a#(b(b(x1))) -> a#(a(x1)) -> a#(b(b(x1))) -> a#(a(x1)) a#(b(b(x1))) -> a#(a(x1)) -> a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(a(x1)) -> a#(x1) -> c#(x1) a#(b(b(x1))) -> a#(x1) -> a#(b(b(x1))) -> a#(a(x1)) a#(b(b(x1))) -> a#(x1) -> a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(x1) -> a#(x1) -> c#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 6/9 DPs: a#(b(b(x1))) -> a#(a(x1)) a#(b(b(x1))) -> a#(x1) TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 interpretation: [0 -&] [c](x0) = [0 -&]x0, [a#](x0) = [0 0]x0, [0 -&] [a](x0) = [2 0 ]x0, [0 0] [b](x0) = [2 0]x0 orientation: a#(b(b(x1))) = [2 2]x1 >= [2 0]x1 = a#(a(x1)) a#(b(b(x1))) = [2 2]x1 >= [0 0]x1 = a#(x1) [0 -&] [0 -&] a(x1) = [2 0 ]x1 >= [2 -&]x1 = b(c(x1)) [2 0] [2 0] a(b(b(x1))) = [4 2]x1 >= [4 2]x1 = b(b(a(a(x1)))) [0 0] c(b(x1)) = [0 0]x1 >= x1 = x1 problem: DPs: a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 Restore Modifier: DPs: a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 EDG Processor: DPs: a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 graph: a#(b(b(x1))) -> a#(a(x1)) -> a#(b(b(x1))) -> a#(a(x1)) Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 interpretation: [-& 0 ] [0] [c](x0) = [-& 0 ]x0 + [0], [a#](x0) = [-& 0 ]x0 + [1], [-& 2 ] [3] [a](x0) = [-& 0 ]x0 + [0], [0 2] [3 ] [b](x0) = [0 0]x0 + [-&] orientation: a#(b(b(x1))) = [0 2]x1 + [3] >= [-& 0 ]x1 + [1] = a#(a(x1)) [-& 2 ] [3] [-& 2 ] [3] a(x1) = [-& 0 ]x1 + [0] >= [-& 0 ]x1 + [0] = b(c(x1)) [2 4] [5] [-& 4 ] [5] a(b(b(x1))) = [0 2]x1 + [3] >= [-& 2 ]x1 + [3] = b(b(a(a(x1)))) [0 0] [0] c(b(x1)) = [0 0]x1 + [0] >= x1 = x1 problem: DPs: TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 Qed