NO

Problem:
 a(a(b(x1))) -> a(c(c(a(a(a(x1))))))
 a(c(x1)) -> b(x1)

Proof:
 String Reversal Processor:
  b(a(a(x1))) -> a(a(a(c(c(a(x1))))))
  c(a(x1)) -> b(x1)
  Unfolding Processor:
   loop length: 16
   terms:
    b(a(a(a(a(a(a(a(a(x84828)))))))))
    a(a(a(c(c(a(a(a(a(a(a(a(x84828))))))))))))
    a(a(a(c(b(a(a(a(a(a(a(x84828)))))))))))
    a(a(a(c(a(a(a(c(c(a(a(a(a(a(x84828))))))))))))))
    a(a(a(b(a(a(c(c(a(a(a(a(a(x84828)))))))))))))
    a(a(a(b(a(a(c(b(a(a(a(a(x84828))))))))))))
    a(a(a(b(a(a(c(a(a(a(c(c(a(a(a(x84828)))))))))))))))
    a(a(a(b(a(a(b(a(a(c(c(a(a(a(x84828))))))))))))))
    a(a(a(b(a(a(a(a(a(c(c(a(c(c(a(a(a(x84828)))))))))))))))))
    a(a(a(b(a(a(a(a(a(c(b(c(c(a(a(a(x84828))))))))))))))))
    a(a(a(b(a(a(a(a(a(c(b(c(b(a(a(x84828)))))))))))))))
    a(a(a(b(a(a(a(a(a(c(b(c(a(a(a(c(c(a(x84828))))))))))))))))))
    a(a(a(b(a(a(a(a(a(c(b(b(a(a(c(c(a(x84828)))))))))))))))))
    a(a(a(b(a(a(a(a(a(c(b(a(a(a(c(c(a(c(c(a(x84828))))))))))))))))))))
    a(a(a(b(a(a(a(a(a(c(a(a(a(c(c(a(a(c(c(a(c(c(a(x84828)))))))))))))))))))))))
    a(a(a(b(a(a(a(a(a(b(a(a(c(c(a(a(c(c(a(c(c(a(x84828))))))))))))))))))))))
   context: a(a(a([])))
   substitution:
    x84828 -> c(c(a(c(c(a(a(c(c(a(c(c(a(x84828)))))))))))))
   Qed