NO
proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination w.r.t. Q of the given QTRS could be disproven:

(0) QTRS
(1) NonTerminationProof [COMPLETE, 0 ms]
(2) NO


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(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   a(b(a(x1))) -> b(b(b(x1)))
   b(a(b(x1))) -> a(b(a(x1)))

Q is empty.

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(1) NonTerminationProof (COMPLETE)
We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure: 
"a b a a b b -> a b a a b b"
a b a a b b -> a b a a b b
by OverlapClosure OC 3"a b a a b b -> b a b a b b
by OverlapClosure OC 3"a b a a b b -> b b a b b b
by OverlapClosure OC 2"a b a -> b b b
by original rule (OC 1)""b a b b -> a b b b
by OverlapClosure OC 2"b a b -> a b a
by original rule (OC 1)""b a b -> b b b
by OverlapClosure OC 2"b a b -> a b a
by original rule (OC 1)""a b a -> b b b
by original rule (OC 1)"""""b a b -> a b a
by original rule (OC 1)"""b a b -> a b a
by original rule (OC 1)"

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(2)
NO