YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 13 ms] (2) QDP (3) QDPOrderProof [EQUIVALENT, 104 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 38 ms] (6) QDP (7) QDPOrderProof [EQUIVALENT, 28 ms] (8) QDP (9) DependencyGraphProof [EQUIVALENT, 0 ms] (10) QDP (11) QDPOrderProof [EQUIVALENT, 311 ms] (12) QDP (13) PisEmptyProof [EQUIVALENT, 0 ms] (14) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(x1))) -> b(x1) b(b(x1)) -> a(a(x1)) a(a(x1)) -> a(b(a(x1))) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: A(a(a(x1))) -> B(x1) B(b(x1)) -> A(a(x1)) B(b(x1)) -> A(x1) A(a(x1)) -> A(b(a(x1))) A(a(x1)) -> B(a(x1)) The TRS R consists of the following rules: a(a(a(x1))) -> b(x1) b(b(x1)) -> a(a(x1)) a(a(x1)) -> a(b(a(x1))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(a(a(x1))) -> B(x1) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: <<< POL(A(x_1)) = [[0A]] + [[0A, -I, 0A]] * x_1 >>> <<< POL(a(x_1)) = [[-I], [-I], [0A]] + [[1A, 0A, 0A], [0A, -I, -I], [1A, 0A, -I]] * x_1 >>> <<< POL(B(x_1)) = [[-I]] + [[0A, 0A, 0A]] * x_1 >>> <<< POL(b(x_1)) = [[-I], [0A], [0A]] + [[0A, 1A, -I], [1A, 0A, 0A], [0A, 1A, 0A]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: b(b(x1)) -> a(a(x1)) a(a(a(x1))) -> b(x1) a(a(x1)) -> a(b(a(x1))) ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: B(b(x1)) -> A(a(x1)) B(b(x1)) -> A(x1) A(a(x1)) -> A(b(a(x1))) A(a(x1)) -> B(a(x1)) The TRS R consists of the following rules: a(a(a(x1))) -> b(x1) b(b(x1)) -> a(a(x1)) a(a(x1)) -> a(b(a(x1))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. B(b(x1)) -> A(x1) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: <<< POL(B(x_1)) = [[-I]] + [[0A, 0A, 0A]] * x_1 >>> <<< POL(b(x_1)) = [[1A], [1A], [-I]] + [[0A, 1A, 1A], [1A, -I, 0A], [-I, -I, -I]] * x_1 >>> <<< POL(A(x_1)) = [[0A]] + [[-I, 0A, 0A]] * x_1 >>> <<< POL(a(x_1)) = [[0A], [1A], [-I]] + [[-I, 0A, 0A], [0A, 1A, 1A], [-I, -I, -I]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: b(b(x1)) -> a(a(x1)) a(a(a(x1))) -> b(x1) a(a(x1)) -> a(b(a(x1))) ---------------------------------------- (6) Obligation: Q DP problem: The TRS P consists of the following rules: B(b(x1)) -> A(a(x1)) A(a(x1)) -> A(b(a(x1))) A(a(x1)) -> B(a(x1)) The TRS R consists of the following rules: a(a(a(x1))) -> b(x1) b(b(x1)) -> a(a(x1)) a(a(x1)) -> a(b(a(x1))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (7) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(a(x1)) -> B(a(x1)) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: <<< POL(B(x_1)) = [[0A]] + [[-I, 0A, -I]] * x_1 >>> <<< POL(b(x_1)) = [[0A], [1A], [0A]] + [[0A, 1A, 0A], [1A, 0A, 0A], [-I, 0A, -I]] * x_1 >>> <<< POL(A(x_1)) = [[-I]] + [[0A, -I, -I]] * x_1 >>> <<< POL(a(x_1)) = [[1A], [0A], [0A]] + [[1A, 0A, 0A], [0A, -I, -I], [0A, -I, 0A]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: b(b(x1)) -> a(a(x1)) a(a(a(x1))) -> b(x1) a(a(x1)) -> a(b(a(x1))) ---------------------------------------- (8) Obligation: Q DP problem: The TRS P consists of the following rules: B(b(x1)) -> A(a(x1)) A(a(x1)) -> A(b(a(x1))) The TRS R consists of the following rules: a(a(a(x1))) -> b(x1) b(b(x1)) -> a(a(x1)) a(a(x1)) -> a(b(a(x1))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (9) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node. ---------------------------------------- (10) Obligation: Q DP problem: The TRS P consists of the following rules: A(a(x1)) -> A(b(a(x1))) The TRS R consists of the following rules: a(a(a(x1))) -> b(x1) b(b(x1)) -> a(a(x1)) a(a(x1)) -> a(b(a(x1))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (11) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(a(x1)) -> A(b(a(x1))) The remaining pairs can at least be oriented weakly. Used ordering: Matrix interpretation [MATRO] with arctic integers [ARCTIC,STERNAGEL_THIEMANN_RTA14]: <<< POL(A(x_1)) = [[0A]] + [[-1A, -1A, 2A]] * x_1 >>> <<< POL(a(x_1)) = [[0A], [-1A], [2A]] + [[-I, -1A, -1A], [-I, 0A, -I], [-1A, 2A, 1A]] * x_1 >>> <<< POL(b(x_1)) = [[2A], [-1A], [-I]] + [[-I, 2A, 1A], [-I, 0A, -I], [1A, -1A, -1A]] * x_1 >>> The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: b(b(x1)) -> a(a(x1)) a(a(a(x1))) -> b(x1) a(a(x1)) -> a(b(a(x1))) ---------------------------------------- (12) Obligation: Q DP problem: P is empty. The TRS R consists of the following rules: a(a(a(x1))) -> b(x1) b(b(x1)) -> a(a(x1)) a(a(x1)) -> a(b(a(x1))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (13) PisEmptyProof (EQUIVALENT) The TRS P is empty. Hence, there is no (P,Q,R) chain. ---------------------------------------- (14) YES