YES

Problem:
 0(1(2(3(4(x1))))) -> 0(2(3(1(4(x1)))))
 0(5(1(2(3(4(x1)))))) -> 0(1(2(5(3(4(x1))))))
 0(5(1(2(3(4(x1)))))) -> 0(5(2(1(3(4(x1))))))
 0(5(1(2(3(4(x1)))))) -> 5(0(2(3(1(4(x1))))))
 0(5(2(3(1(4(x1)))))) -> 0(1(5(2(3(4(x1))))))

Proof:
 KBO Processor:
  weight function:
   w0 = 1
   w(5) = w(1) = w(2) = w(3) = w(4) = 1
   w(0) = 0
  precedence:
   0 > 3 > 4 > 5 > 1 > 2
  problem:
   
  Qed