YES After renaming modulo { a->0, b->1, c->2, d->3, f->4, g->5 }, it remains to prove termination of the 9-rule system { 0 1 2 0 -> 1 0 2 1 0 1 , 0 3 -> 2 , 0 4 4 -> 5 , 1 5 -> 5 1 , 2 -> 4 4 , 2 0 2 -> 1 2 0 1 2 , 2 3 -> 0 0 , 5 -> 2 0 , 5 -> 3 3 3 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 12 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 18 | | 0 1 | \ / 3 is interpreted by / \ | 1 7 | | 0 1 | \ / 4 is interpreted by / \ | 1 9 | | 0 1 | \ / 5 is interpreted by / \ | 1 30 | | 0 1 | \ / After renaming modulo { 0->0, 1->1, 2->2, 4->3, 5->4 }, it remains to prove termination of the 6-rule system { 0 1 2 0 -> 1 0 2 1 0 1 , 0 3 3 -> 4 , 1 4 -> 4 1 , 2 -> 3 3 , 2 0 2 -> 1 2 0 1 2 , 4 -> 2 0 } Applying the dependency pairs transformation. After renaming modulo { (0,true)->0, (1,false)->1, (2,false)->2, (0,false)->3, (1,true)->4, (2,true)->5, (3,false)->6, (4,true)->7, (4,false)->8 }, it remains to prove termination of the 22-rule system { 0 1 2 3 -> 4 3 2 1 3 1 , 0 1 2 3 -> 0 2 1 3 1 , 0 1 2 3 -> 5 1 3 1 , 0 1 2 3 -> 4 3 1 , 0 1 2 3 -> 0 1 , 0 1 2 3 -> 4 , 0 6 6 -> 7 , 4 8 -> 7 1 , 4 8 -> 4 , 5 3 2 -> 4 2 3 1 2 , 5 3 2 -> 5 3 1 2 , 5 3 2 -> 0 1 2 , 5 3 2 -> 4 2 , 5 3 2 -> 5 , 7 -> 5 3 , 7 -> 0 , 3 1 2 3 ->= 1 3 2 1 3 1 , 3 6 6 ->= 8 , 1 8 ->= 8 1 , 2 ->= 6 6 , 2 3 2 ->= 1 2 3 1 2 , 8 ->= 2 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 2 | | 0 1 | \ / 3 is interpreted by / \ | 1 0 | | 0 1 | \ / 4 is interpreted by / \ | 1 0 | | 0 1 | \ / 5 is interpreted by / \ | 1 2 | | 0 1 | \ / 6 is interpreted by / \ | 1 1 | | 0 1 | \ / 7 is interpreted by / \ | 1 2 | | 0 1 | \ / 8 is interpreted by / \ | 1 2 | | 0 1 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4, 8->5, 7->6, 5->7, 6->8 }, it remains to prove termination of the 11-rule system { 0 1 2 3 -> 0 2 1 3 1 , 4 5 -> 6 1 , 7 3 2 -> 4 2 3 1 2 , 7 3 2 -> 7 3 1 2 , 6 -> 7 3 , 3 1 2 3 ->= 1 3 2 1 3 1 , 3 8 8 ->= 5 , 1 5 ->= 5 1 , 2 ->= 8 8 , 2 3 2 ->= 1 2 3 1 2 , 5 ->= 2 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 3: 0 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 1 | \ / 2 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 1 0 | \ / 4 is interpreted by / \ | 1 0 1 | | 0 1 0 | | 0 0 0 | \ / 5 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 1 0 | \ / 6 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / 7 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / 8 is interpreted by / \ | 1 0 0 | | 0 1 0 | | 0 0 0 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3, 7->4, 4->5, 6->6, 8->7, 5->8 }, it remains to prove termination of the 10-rule system { 0 1 2 3 -> 0 2 1 3 1 , 4 3 2 -> 5 2 3 1 2 , 4 3 2 -> 4 3 1 2 , 6 -> 4 3 , 3 1 2 3 ->= 1 3 2 1 3 1 , 3 7 7 ->= 8 , 1 8 ->= 8 1 , 2 ->= 7 7 , 2 3 2 ->= 1 2 3 1 2 , 8 ->= 2 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 0 | | 0 1 | \ / 3 is interpreted by / \ | 1 0 | | 0 1 | \ / 4 is interpreted by / \ | 1 0 | | 0 1 | \ / 5 is interpreted by / \ | 1 0 | | 0 1 | \ / 6 is interpreted by / \ | 1 1 | | 0 1 | \ / 7 is interpreted by / \ | 1 0 | | 0 1 | \ / 8 is interpreted by / \ | 1 0 | | 0 1 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4, 5->5, 7->6, 8->7 }, it remains to prove termination of the 9-rule system { 0 1 2 3 -> 0 2 1 3 1 , 4 3 2 -> 5 2 3 1 2 , 4 3 2 -> 4 3 1 2 , 3 1 2 3 ->= 1 3 2 1 3 1 , 3 6 6 ->= 7 , 1 7 ->= 7 1 , 2 ->= 6 6 , 2 3 2 ->= 1 2 3 1 2 , 7 ->= 2 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 0 | | 0 1 | \ / 3 is interpreted by / \ | 1 0 | | 0 1 | \ / 4 is interpreted by / \ | 1 1 | | 0 1 | \ / 5 is interpreted by / \ | 1 0 | | 0 1 | \ / 6 is interpreted by / \ | 1 0 | | 0 1 | \ / 7 is interpreted by / \ | 1 0 | | 0 1 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3, 4->4, 6->5, 7->6 }, it remains to prove termination of the 8-rule system { 0 1 2 3 -> 0 2 1 3 1 , 4 3 2 -> 4 3 1 2 , 3 1 2 3 ->= 1 3 2 1 3 1 , 3 5 5 ->= 6 , 1 6 ->= 6 1 , 2 ->= 5 5 , 2 3 2 ->= 1 2 3 1 2 , 6 ->= 2 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 5: 0 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 1 | | 0 0 0 0 1 | \ / 2 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 1 0 | | 0 1 0 0 0 | | 0 1 0 0 0 | \ / 4 is interpreted by / \ | 1 0 1 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 5 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 6 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 1 0 0 0 | | 0 1 0 0 0 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3, 5->4, 6->5 }, it remains to prove termination of the 7-rule system { 0 1 2 3 -> 0 2 1 3 1 , 3 1 2 3 ->= 1 3 2 1 3 1 , 3 4 4 ->= 5 , 1 5 ->= 5 1 , 2 ->= 4 4 , 2 3 2 ->= 1 2 3 1 2 , 5 ->= 2 3 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 5: 0 is interpreted by / \ | 1 0 1 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 1 0 | | 0 0 0 1 0 | | 0 0 0 0 0 | \ / 2 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 1 | | 0 0 0 0 1 | | 0 0 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 1 0 0 0 | | 0 1 0 0 0 | | 0 1 0 0 0 | \ / 4 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 5 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 1 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | \ / After renaming modulo { 3->0, 1->1, 2->2, 4->3, 5->4 }, it remains to prove termination of the 6-rule system { 0 1 2 0 ->= 1 0 2 1 0 1 , 0 3 3 ->= 4 , 1 4 ->= 4 1 , 2 ->= 3 3 , 2 0 2 ->= 1 2 0 1 2 , 4 ->= 2 0 } The system is trivially terminating.