YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(c(a(a(a(a(a(x1))))))))) -> a(a(a(a(a(a(b(c(c(a(a(b(c(c(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(c(c(b(a(x1))))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(c(c(b(a(x1))))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(c(c(b(x)))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(c(c(b(x)))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(c(c(b(x)))))))) -> c(c(b(a(a(c(c(b(a(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 513, 514, 515, 516, 517, 518, 519, 520, 521, 522, 523, 524, 525, 526, 527, 528, 529, 530, 531, 532, 533, 534, 535, 536, 537, 538 Node 513 is start node and node 514 is final node. Those nodes are connected through the following edges: * 513 to 515 labelled c_1(0)* 514 to 514 labelled #_1(0)* 515 to 516 labelled c_1(0)* 516 to 517 labelled b_1(0)* 517 to 518 labelled a_1(0)* 518 to 519 labelled a_1(0)* 519 to 520 labelled c_1(0)* 520 to 521 labelled c_1(0)* 521 to 522 labelled b_1(0)* 522 to 523 labelled a_1(0)* 522 to 527 labelled c_1(1)* 523 to 524 labelled a_1(0)* 523 to 527 labelled c_1(1)* 524 to 525 labelled a_1(0)* 524 to 527 labelled c_1(1)* 525 to 526 labelled a_1(0)* 525 to 527 labelled c_1(1)* 526 to 514 labelled a_1(0)* 526 to 527 labelled c_1(1)* 527 to 528 labelled c_1(1)* 528 to 529 labelled b_1(1)* 529 to 530 labelled a_1(1)* 530 to 531 labelled a_1(1)* 531 to 532 labelled c_1(1)* 532 to 533 labelled c_1(1)* 533 to 534 labelled b_1(1)* 534 to 535 labelled a_1(1)* 534 to 527 labelled c_1(1)* 535 to 536 labelled a_1(1)* 535 to 527 labelled c_1(1)* 536 to 537 labelled a_1(1)* 536 to 527 labelled c_1(1)* 537 to 538 labelled a_1(1)* 537 to 527 labelled c_1(1)* 538 to 514 labelled a_1(1)* 538 to 527 labelled c_1(1) ---------------------------------------- (6) YES