YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(b(a(b(a(x1)))))))))) -> a(a(b(a(b(a(b(a(b(a(a(b(x1)))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(a(b(a(x1)))))))))) -> b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(b(a(a(b(a(x1)))))))))) -> b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(b(a(a(b(x))))))))) -> b(a(a(b(a(b(a(b(a(b(a(x))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(a(b(x))))))))) -> b(a(a(b(a(b(a(b(a(b(a(x))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(b(a(a(b(x))))))))) -> b(a(a(b(a(b(a(b(a(b(a(x))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 582, 583, 584, 585, 586, 587, 588, 589, 590, 591, 592, 593, 594, 595, 596, 597, 598, 599, 600, 601, 602, 603 Node 582 is start node and node 583 is final node. Those nodes are connected through the following edges: * 582 to 584 labelled b_1(0)* 583 to 583 labelled #_1(0)* 584 to 585 labelled a_1(0)* 585 to 586 labelled a_1(0)* 586 to 587 labelled b_1(0)* 587 to 588 labelled a_1(0)* 587 to 594 labelled b_1(1)* 588 to 589 labelled b_1(0)* 589 to 590 labelled a_1(0)* 589 to 594 labelled b_1(1)* 590 to 591 labelled b_1(0)* 591 to 592 labelled a_1(0)* 591 to 594 labelled b_1(1)* 592 to 593 labelled b_1(0)* 593 to 583 labelled a_1(0)* 593 to 594 labelled b_1(1)* 594 to 595 labelled a_1(1)* 595 to 596 labelled a_1(1)* 596 to 597 labelled b_1(1)* 597 to 598 labelled a_1(1)* 597 to 594 labelled b_1(1)* 598 to 599 labelled b_1(1)* 599 to 600 labelled a_1(1)* 599 to 594 labelled b_1(1)* 600 to 601 labelled b_1(1)* 601 to 602 labelled a_1(1)* 601 to 594 labelled b_1(1)* 602 to 603 labelled b_1(1)* 603 to 583 labelled a_1(1)* 603 to 594 labelled b_1(1) ---------------------------------------- (6) YES