YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(a(a(a(x1))))))))) -> a(a(a(a(a(a(a(a(b(a(a(b(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(a(b(a(x1))))))))) -> b(a(b(a(a(b(a(a(a(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(a(a(b(a(x1))))))))) -> b(a(b(a(a(b(a(a(a(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(a(a(b(x)))))))) -> b(a(b(a(a(b(a(a(a(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(a(b(x)))))))) -> b(a(b(a(a(b(a(a(a(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(a(a(b(x)))))))) -> b(a(b(a(a(b(a(a(a(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 447, 448, 475, 476, 477, 478, 479, 480, 481, 482, 483, 484, 485, 486, 487, 488, 489, 490, 491, 492, 493, 494, 495, 496, 497, 498 Node 447 is start node and node 448 is final node. Those nodes are connected through the following edges: * 447 to 475 labelled b_1(0)* 448 to 448 labelled #_1(0)* 475 to 476 labelled a_1(0)* 476 to 477 labelled b_1(0)* 477 to 478 labelled a_1(0)* 478 to 479 labelled a_1(0)* 479 to 480 labelled b_1(0)* 480 to 481 labelled a_1(0)* 480 to 487 labelled b_1(1)* 481 to 482 labelled a_1(0)* 481 to 487 labelled b_1(1)* 482 to 483 labelled a_1(0)* 482 to 487 labelled b_1(1)* 483 to 484 labelled a_1(0)* 483 to 487 labelled b_1(1)* 484 to 485 labelled a_1(0)* 484 to 487 labelled b_1(1)* 485 to 486 labelled a_1(0)* 485 to 487 labelled b_1(1)* 486 to 448 labelled a_1(0)* 486 to 487 labelled b_1(1)* 487 to 488 labelled a_1(1)* 488 to 489 labelled b_1(1)* 489 to 490 labelled a_1(1)* 490 to 491 labelled a_1(1)* 491 to 492 labelled b_1(1)* 492 to 493 labelled a_1(1)* 492 to 487 labelled b_1(1)* 493 to 494 labelled a_1(1)* 493 to 487 labelled b_1(1)* 494 to 495 labelled a_1(1)* 494 to 487 labelled b_1(1)* 495 to 496 labelled a_1(1)* 495 to 487 labelled b_1(1)* 496 to 497 labelled a_1(1)* 496 to 487 labelled b_1(1)* 497 to 498 labelled a_1(1)* 497 to 487 labelled b_1(1)* 498 to 448 labelled a_1(1)* 498 to 487 labelled b_1(1) ---------------------------------------- (6) YES