YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(b(c(a(a(a(a(a(x1))))))))) -> a(a(a(a(a(a(b(b(c(a(a(b(b(c(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(c(b(b(a(x1))))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(c(b(b(a(x1))))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(c(b(b(x)))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(c(b(b(x)))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(c(b(b(x)))))))) -> c(b(b(a(a(c(b(b(a(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 487, 488, 489, 490, 491, 492, 493, 494, 495, 496, 497, 498, 499, 500, 501, 502, 503, 504, 505, 506, 507, 508, 509, 510, 511, 512 Node 487 is start node and node 488 is final node. Those nodes are connected through the following edges: * 487 to 489 labelled c_1(0)* 488 to 488 labelled #_1(0)* 489 to 490 labelled b_1(0)* 490 to 491 labelled b_1(0)* 491 to 492 labelled a_1(0)* 492 to 493 labelled a_1(0)* 493 to 494 labelled c_1(0)* 494 to 495 labelled b_1(0)* 495 to 496 labelled b_1(0)* 496 to 497 labelled a_1(0)* 496 to 501 labelled c_1(1)* 497 to 498 labelled a_1(0)* 497 to 501 labelled c_1(1)* 498 to 499 labelled a_1(0)* 498 to 501 labelled c_1(1)* 499 to 500 labelled a_1(0)* 499 to 501 labelled c_1(1)* 500 to 488 labelled a_1(0)* 500 to 501 labelled c_1(1)* 501 to 502 labelled b_1(1)* 502 to 503 labelled b_1(1)* 503 to 504 labelled a_1(1)* 504 to 505 labelled a_1(1)* 505 to 506 labelled c_1(1)* 506 to 507 labelled b_1(1)* 507 to 508 labelled b_1(1)* 508 to 509 labelled a_1(1)* 508 to 501 labelled c_1(1)* 509 to 510 labelled a_1(1)* 509 to 501 labelled c_1(1)* 510 to 511 labelled a_1(1)* 510 to 501 labelled c_1(1)* 511 to 512 labelled a_1(1)* 511 to 501 labelled c_1(1)* 512 to 488 labelled a_1(1)* 512 to 501 labelled c_1(1) ---------------------------------------- (6) YES