YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(a(a(x1)))))))) -> a(a(a(a(a(a(a(b(a(a(a(b(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(b(a(x1)))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(a(b(a(x1)))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(a(b(x))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(b(x))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(a(b(x))))))) -> b(a(b(a(a(a(b(a(a(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 159, 160, 161, 162, 163, 164, 165, 166, 167, 168, 169, 170 Node 84 is start node and node 85 is final node. Those nodes are connected through the following edges: * 84 to 86 labelled b_1(0)* 85 to 85 labelled #_1(0)* 86 to 87 labelled a_1(0)* 87 to 88 labelled b_1(0)* 88 to 89 labelled a_1(0)* 89 to 90 labelled a_1(0)* 90 to 91 labelled a_1(0)* 91 to 92 labelled b_1(0)* 92 to 93 labelled a_1(0)* 92 to 159 labelled b_1(1)* 93 to 94 labelled a_1(0)* 93 to 159 labelled b_1(1)* 94 to 95 labelled a_1(0)* 94 to 159 labelled b_1(1)* 95 to 96 labelled a_1(0)* 95 to 159 labelled b_1(1)* 96 to 97 labelled a_1(0)* 96 to 159 labelled b_1(1)* 97 to 85 labelled a_1(0)* 97 to 159 labelled b_1(1)* 159 to 160 labelled a_1(1)* 160 to 161 labelled b_1(1)* 161 to 162 labelled a_1(1)* 162 to 163 labelled a_1(1)* 163 to 164 labelled a_1(1)* 164 to 165 labelled b_1(1)* 165 to 166 labelled a_1(1)* 165 to 159 labelled b_1(1)* 166 to 167 labelled a_1(1)* 166 to 159 labelled b_1(1)* 167 to 168 labelled a_1(1)* 167 to 159 labelled b_1(1)* 168 to 169 labelled a_1(1)* 168 to 159 labelled b_1(1)* 169 to 170 labelled a_1(1)* 169 to 159 labelled b_1(1)* 170 to 85 labelled a_1(1)* 170 to 159 labelled b_1(1) ---------------------------------------- (6) YES