NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 362 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(0(0(0(x1)))) -> 0(0(1(1(x1)))) 1(0(0(1(x1)))) -> 0(0(1(0(x1)))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "0 0 0 0 0 0 1 0 1 0 1 0 -> 0 0 0 0 0 0 1 0 1 0 1 0" 0 0 0 0 0 0 1 0 1 0 1 0 -> 0 0 0 0 0 0 1 0 1 0 1 0 by OverlapClosure OC 3"0 0 0 0 0 0 1 0 1 0 1 0 -> 0 0 0 0 1 0 0 1 1 0 1 0 by OverlapClosure OC 3"0 0 0 0 0 0 1 0 1 0 1 0 -> 0 0 0 0 1 0 0 0 0 0 1 0 by OverlapClosure OC 3"0 0 0 0 0 0 1 0 1 0 1 0 -> 0 0 1 0 0 1 0 0 0 0 1 0 by OverlapClosure OC 2"0 0 0 0 -> 0 0 1 1 by original rule (OC 1)""1 0 0 1 0 1 0 1 0 -> 0 0 1 0 0 0 0 1 0 by OverlapClosure OC 2"1 0 0 1 0 1 0 1 0 -> 0 0 1 0 0 1 0 0 1 by OverlapClosure OC 3"1 0 0 1 0 1 0 1 0 -> 0 0 1 1 0 0 1 0 1 by OverlapClosure OC 3"1 0 0 1 0 1 0 1 0 -> 0 0 1 1 1 0 0 1 1 by OverlapClosure OC 2"1 0 0 1 0 1 0 1 -> 0 0 1 1 1 0 0 0 by OverlapClosure OC 3"1 0 0 1 0 1 0 1 -> 0 0 0 0 1 0 0 0 by OverlapClosure OC 3"1 0 0 1 0 1 0 1 -> 0 0 1 0 0 1 0 0 by OverlapClosure OC 3"1 0 0 1 0 1 0 1 -> 0 0 1 1 0 0 1 0 by OverlapClosure OC 2"1 0 0 1 0 1 -> 0 0 1 1 1 0 by OverlapClosure OC 3"1 0 0 1 0 1 -> 0 0 0 0 1 0 by OverlapClosure OC 2"1 0 0 1 -> 0 0 1 0 by original rule (OC 1)""1 0 0 1 -> 0 0 1 0 by original rule (OC 1)"""0 0 0 0 -> 0 0 1 1 by original rule (OC 1)"""1 0 0 1 -> 0 0 1 0 by original rule (OC 1)"""1 0 0 1 -> 0 0 1 0 by original rule (OC 1)"""1 0 0 1 -> 0 0 1 0 by original rule (OC 1)"""0 0 0 0 -> 0 0 1 1 by original rule (OC 1)"""0 0 0 0 -> 0 0 1 1 by original rule (OC 1)"""1 0 0 1 -> 0 0 1 0 by original rule (OC 1)"""1 0 0 1 -> 0 0 1 0 by original rule (OC 1)"""1 0 0 1 -> 0 0 1 0 by original rule (OC 1)""""1 0 0 1 -> 0 0 1 0 by original rule (OC 1)"""0 0 0 0 -> 0 0 1 1 by original rule (OC 1)"""1 0 0 1 -> 0 0 1 0 by original rule (OC 1)" ---------------------------------------- (2) NO