YES After renaming modulo { a->0, b->1 }, it remains to prove termination of the 2-rule system { 0 0 0 1 -> 1 0 0 0 , 1 1 -> 0 1 0 1 } Applying the dependency pairs transformation. After renaming modulo { (0,true)->0, (0,false)->1, (1,false)->2, (1,true)->3 }, it remains to prove termination of the 10-rule system { 0 1 1 2 -> 3 1 1 1 , 0 1 1 2 -> 0 1 1 , 0 1 1 2 -> 0 1 , 0 1 1 2 -> 0 , 3 2 -> 0 2 1 2 , 3 2 -> 3 1 2 , 3 2 -> 0 2 , 3 2 -> 3 , 1 1 1 2 ->= 2 1 1 1 , 2 2 ->= 1 2 1 2 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 0 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 1 | | 0 1 | \ / 3 is interpreted by / \ | 1 1 | | 0 1 | \ / After renaming modulo { 0->0, 1->1, 2->2, 3->3 }, it remains to prove termination of the 5-rule system { 0 1 1 2 -> 3 1 1 1 , 3 2 -> 0 2 1 2 , 3 2 -> 3 1 2 , 1 1 1 2 ->= 2 1 1 1 , 2 2 ->= 1 2 1 2 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 5: 0 is interpreted by / \ | 1 0 1 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 1 0 | | 0 0 0 0 1 | | 0 0 1 0 0 | \ / 2 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 1 | | 0 1 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 0 0 | | 0 1 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | | 0 0 0 0 0 | \ / After renaming modulo { 3->0, 2->1, 0->2, 1->3 }, it remains to prove termination of the 4-rule system { 0 1 -> 2 1 3 1 , 0 1 -> 0 3 1 , 3 3 3 1 ->= 1 3 3 3 , 1 1 ->= 3 1 3 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 is interpreted by / \ | 1 1 | | 0 1 | \ / 1 is interpreted by / \ | 1 0 | | 0 1 | \ / 2 is interpreted by / \ | 1 0 | | 0 1 | \ / 3 is interpreted by / \ | 1 0 | | 0 1 | \ / After renaming modulo { 0->0, 1->1, 3->2 }, it remains to prove termination of the 3-rule system { 0 1 -> 0 2 1 , 2 2 2 1 ->= 1 2 2 2 , 1 1 ->= 2 1 2 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 6: 0 is interpreted by / \ | 1 0 1 0 0 0 | | 0 1 0 0 0 0 | | 0 0 0 0 0 0 | | 0 0 0 0 0 0 | | 0 0 0 0 0 0 | | 0 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 0 0 0 | | 0 1 0 0 0 0 | | 0 1 0 0 0 0 | | 0 0 0 0 0 0 | | 0 0 0 0 0 1 | | 0 1 0 0 0 0 | \ / 2 is interpreted by / \ | 1 0 0 0 0 0 | | 0 1 0 0 0 0 | | 0 0 0 1 0 0 | | 0 0 0 0 1 0 | | 0 0 0 0 0 1 | | 0 0 0 1 0 0 | \ / After renaming modulo { 2->0, 1->1 }, it remains to prove termination of the 2-rule system { 0 0 0 1 ->= 1 0 0 0 , 1 1 ->= 0 1 0 1 } The system is trivially terminating.