YES

Problem:
 c(b(a(a(x1)))) -> a(a(b(a(a(b(c(b(a(c(x1))))))))))

Proof:
 Bounds Processor:
  bound: 1
  enrichment: match
  automaton:
   final states: {1}
   transitions:
    b0(4) -> 5*
    b0(9) -> 10*
    b0(6) -> 7*
    f30() -> 2*
    a1(13) -> 14*
    a1(20) -> 21*
    a1(17) -> 18*
    a1(21) -> 22*
    a1(18) -> 19*
    c1(12) -> 13*
    c1(15) -> 16*
    b1(16) -> 17*
    b1(19) -> 20*
    b1(14) -> 15*
    a0(3) -> 4*
    a0(11) -> 1*
    a0(10) -> 11*
    a0(8) -> 9*
    a0(7) -> 8*
    c0(2) -> 3*
    c0(5) -> 6*
    11 -> 12*
    22 -> 6*
    1 -> 3*
  problem:
   
  Qed