NO

Problem:
 c(a(b(a(x1)))) -> a(b(a(b(c(c(a(x1)))))))

Proof:
 String Reversal Processor:
  a(b(a(c(x1)))) -> a(c(c(b(a(b(a(x1)))))))
  Unfolding Processor:
   loop length: 4
   terms:
    a(b(a(c(c(b(a(c(c(x130)))))))))
    a(c(c(b(a(b(a(c(b(a(c(c(x130))))))))))))
    a(c(c(b(a(c(c(b(a(b(a(b(a(c(c(x130)))))))))))))))
    a(c(c(b(a(c(c(b(a(b(a(c(c(b(a(b(a(c(x130))))))))))))))))))
   context: a(c(c(b(a(c(c(b([]))))))))
   substitution:
    x130 -> b(a(b(a(x130))))
   Qed