YES

Problem:
 b(a(a(a(b(a(a(x1))))))) -> a(a(a(b(b(a(a(a(b(x1)))))))))

Proof:
 String Reversal Processor:
  a(a(b(a(a(a(b(x1))))))) -> b(a(a(a(b(b(a(a(a(x1)))))))))
  Bounds Processor:
   bound: 1
   enrichment: match
   automaton:
    final states: {1}
    transitions:
     b1(25) -> 26*
     b1(29) -> 30*
     b1(24) -> 25*
     f20() -> 2*
     b0(10) -> 1*
     b0(5) -> 6*
     b0(6) -> 7*
     a0(3) -> 4*
     a0(4) -> 5*
     a0(2) -> 3*
     a0(8) -> 9*
     a0(9) -> 10*
     a0(7) -> 8*
     a1(21) -> 22*
     a1(27) -> 28*
     a1(26) -> 27*
     a1(23) -> 24*
     a1(22) -> 23*
     a1(28) -> 29*
     30 -> 5*
     6 -> 21*
     1 -> 23,3,4
   problem:
    
   Qed