YES

Problem:
 b(b(c(a(b(c(x1)))))) -> a(b(b(c(b(c(a(x1)))))))

Proof:
 String Reversal Processor:
  c(b(a(c(b(b(x1)))))) -> a(c(b(c(b(b(a(x1)))))))
  Bounds Processor:
   bound: 1
   enrichment: match
   automaton:
    final states: {4}
    transitions:
     a1(19) -> 20*
     a1(13) -> 14*
     b1(15) -> 16*
     b1(14) -> 15*
     b1(17) -> 18*
     c1(16) -> 17*
     c1(18) -> 19*
     c0(4) -> 4*
     a0(4) -> 4*
     b0(4) -> 4*
     4 -> 13*
     20 -> 4*
   problem:
    
   Qed