NO
proof of /export/starexec/sandbox/benchmark/theBenchmark.xml
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination w.r.t. Q of the given QTRS could be disproven:

(0) QTRS
(1) NonTerminationProof [COMPLETE, 28 ms]
(2) NO


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(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   c(b(a(b(a(x1))))) -> a(b(a(b(a(b(c(b(c(x1)))))))))

Q is empty.

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(1) NonTerminationProof (COMPLETE)
We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure: 
"c b a b a b a b a b a b a -> a b a b a b c b a b a b a b a b a b a b c b c b a b c b c"
c b a b a b a b a b a b a -> a b a b a b c b a b a b a b a b a b a b c b c b a b c b c
by OverlapClosure OC 2"c b a b a -> a b a b a b c b c
by original rule (OC 1)""c b a b a b a b a -> a b a b a b a b a b a b c b c b a b c b c
by OverlapClosure OC 3"c b a b a b a b a -> a b a b a b c b a b a b a b c b c
by OverlapClosure OC 2"c b a b a -> a b a b a b c b c
by original rule (OC 1)""c b a b a -> a b a b a b c b c
by original rule (OC 1)"""c b a b a -> a b a b a b c b c
by original rule (OC 1)""

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(2)
NO