YES

Problem:
 b(a(a(b(a(x1))))) -> a(a(b(b(a(a(b(x1)))))))

Proof:
 String Reversal Processor:
  a(b(a(a(b(x1))))) -> b(a(a(b(b(a(a(x1)))))))
  Bounds Processor:
   bound: 1
   enrichment: match
   automaton:
    final states: {1}
    transitions:
     b1(11) -> 12*
     b1(12) -> 13*
     b1(15) -> 16*
     f20() -> 2*
     b0(5) -> 6*
     b0(4) -> 5*
     b0(8) -> 1*
     a0(3) -> 4*
     a0(6) -> 7*
     a0(2) -> 3*
     a0(7) -> 8*
     a1(13) -> 14*
     a1(10) -> 11*
     a1(14) -> 15*
     a1(9) -> 10*
     16 -> 11,4
     1 -> 10,3
     5 -> 9*
   problem:
    
   Qed